Answer:
319.15^{o}C[/tex]
Explanation:
When all other variables are constant, we are allowed to use the formula
![\frac{T_{2} }{V_{2} } = \frac{T_{1} }{V_{1} } \\Which can be rewritten as T_{2} = \frac{T_{1} V_{2} }{V_{1} }if you make T2 the subject of the formula. This formula is true only if temperature is in Kelvin not degrees Celsius so T1 must be converted to KelvinNow to calculate T2[tex]T_{2}= \frac{296.15K*3.38.10^{3}L }{1.69.10^{3}L }= 592.3K](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B2%7D%20%7D%7BV_%7B2%7D%20%7D%20%3D%20%5Cfrac%7BT_%7B1%7D%20%7D%7BV_%7B1%7D%20%7D%20%5C%5C%3C%2Fp%3E%3Cp%3EWhich%20can%20be%20rewritten%20as%20T_%7B2%7D%20%3D%20%5Cfrac%7BT_%7B1%7D%20V_%7B2%7D%20%7D%7BV_%7B1%7D%20%7D%3C%2Fp%3E%3Cp%3Eif%20you%20make%20T2%20the%20subject%20of%20the%20formula.%20This%20formula%20is%20true%20only%20if%20temperature%20is%20in%20Kelvin%20not%20degrees%20Celsius%20so%20T1%20must%20be%20converted%20to%20Kelvin%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3ENow%20to%20calculate%20T2%3C%2Fp%3E%3Cp%3E%5Btex%5DT_%7B2%7D%3D%20%5Cfrac%7B296.15K%2A3.38.10%5E%7B3%7DL%20%7D%7B1.69.10%5E%7B3%7DL%20%7D%3D%20592.3K)
= 
D, the energy of formation is equal to the dissociation. so from magnesium ions and Hydrogen ions, when they form the lattice energy is equal to formation-dissociation, as they aren't going to dissociate (fixed in lattice) the formation should be the same as the the overall lattice energy.
Answer:
yqaeh
Explanation:
Electrolysis of acidified water
Water is a poor conductor of electricity, but it does contain some hydrogen ions , H +, and hydroxide ions, OH -. These ions are formed when a small proportion of water molecules naturally dissociate . ... H + ions are attracted to the cathode , gain electrons and form hydrogen gas.
They're going to fall apart.
<h3>
What most molecules will likely experience over time?</h3>
A system's entropy cannot decrease unless heat is being lost from it. This indicates that entropy cannot decrease in a closed system (i.e., nothing enters or leaves, and that means nothing at all), so it must either remain constant or rise. Entropy can decrease, rise, or stay constant in an open system when movement between the system and its surroundings is conceivable. Both of these outcomes leave open the option of a constant state.
Entropy:-
The quantity of atom-alignment combinations that can exist in a system is known as entropy. The quantity of energy that cannot be used for work can also be calculated from an object's entropy.
Learn more about Entropy here:-
brainly.com/question/17241209
#SPJ4
Explanation:
Since this is an equilibrium problem, we apply le chatelier principle. This principle states that whenever a system at equilibrium is disturbed due to change in several factors, it would move in a way to annul such change.
C2H4(g) + Cl2 ⇔ 2C2H4Cl2(g)
When the concentration of C2H4 is increased, there is more reactant sin the system. In order to annul this change, the equilibrium position will shift to the right favoring product formation.
When the concentration of C2H4Cl2 is increased, there is more product in the system. To annul this change, the equilibrium position will shift to the left, favoring reactant formation.
