All categories

3 years ago

Is molar mass more accurate at low or high temperatures?

1 answer:

5 0

A number of factors combine to make high conversion molecular weight ... to higher molecular weights, because the larger polymer molecules are the most likely to ... the polymerization is performed at rising temperatures, rather than isothermally, ... had a normal curve with a small fraction of low-molecular weight oligomers.

You might be interested in

Indicate the types of forces that are involved between the solute and solvent when forming a homogeneous solution between ch3ch2

Bess [88]

Answer:
Dispersion Forces are found between n-Pentane (CH₃-CH₂-CH₂-CH₂-CH₃) and n-Hexane (CH₃-CH₂-CH₂-CH₂-CH₂-CH₃).

Explanation:
Dispersion Forces are present and developed by those compounds which are non-polar in nature. In given statement n-Pentane and n-Hexane both are non-polar in nature as the electronegativity difference between Hydrogen atoms and Carbon atoms is less than 0.4.
When non-polar molecules approaches each other, a Dipole is induced in one of them, this step is known as Instantaneous Dipole, This generated Dipole on approaching another non-polar molecule induces dipole in it and the process propagates. Hence, creating intermolecular interactions.

8 0

3 years ago

Read 2 more answers

How many kj of heat are needed to completely melt 32.3 g of h2o, given that the water is at its melting point? the heat of fusio

timurjin [86]

Answer: fourth option, 10.8 kJ

Explanation:

The heat of fusion, also named latent heat of fusion, is the amount of heat energy required to change the state of a substance from solid to liquid (at constant pressure).

The data of the heat of fusions of the substances are reported in tables and they can be shown either per mole or per gram of substance.

In this case we have that the heat of fusion for water is reported per mole: 6.02 kJ/mole.

The formula to calculate how many kJ of heat (total heat) are needed to completely melt 32.3 g of water, given that the water is at its melting point is:

Heat = number of moles × heat of fusion

The calculations are:

number of moles = mass / molar mass

number of moles = 32.3 g / 18.015 g/mol = 1.79 mol

Heat = 1.79 mol × 6.02 kJ / mol = 10.8 kJ ← answer

5 0

3 years ago

Read 2 more answers

A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced? 0.538 mol, O2 1.86 mol,

zlopas [31]

Answer:

O 2 has a mass of 1.78g

Explanation:

We are at STP and that means we have to use the ideal gas law equation!

P represents pressure (could have units of atm, depending on the units of the universal gas constant)

V represents volume (must have units of liters)

n represents the number of moles

R is the universal gas constant (has units of

× a t m

m o l

)

T represents the temperature, which must be in Kelvins.

Next, list your known and unknown variables. Our only unknown is the number of moles of

(

)

. Our known variables are P,V,R, and T.

At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821

Now we have to rearrange the equation to solve for n

atm

1.25

0.0821

Lxxatm

273

0.05577

To get the mass of

, we just have to use the molar mass of oxygen as a conversion factor:

0.0577

mol

32.00

mol

= 1.78g

3 0

3 years ago

Read 2 more answers

When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be

Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

$AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)$

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

0.269 M = $\frac{\text{no. of moles}}{1.14 L}$

no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.307 mol = $\frac{mass}{143.32 g/mol}$

mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

8 0

3 years ago

Which of the following is equal to 5.3 mm3? 5.3 x 10-6 m3 5.3 x 10-9 m3 5.3 x 10-6 cm3 5.3 x 103 cm3

Shalnov [3]

The answer to this item is determined by using the proper conversion factors and the dimensional analysis. For the given units, meter and centimeters, the conversion from millimeters are as shown below,

1 m = 1000 mm
1 cm = 10 mm

Conversion of 5.3 mm³ to m³.

= (5.3 mm³)(1 m/1000 mm)³ = 5.3 x 10⁻⁹ m³

Conversion of 5.3 mm³ to cm³.

= (5.3 mm³)(1 cm/10 mm)³ = 5.3 x 10⁻³ cm³

The answer to this item is therefore letter B. 5.3 x 10⁻⁹ m³.

3 0

3 years ago