The first shell is full at 2 electrons, the next 2 shells are full at 8 electrons, and any shells after that are full at 16 electrons
Answer:
Explanation:
the chemical equilibrium constant can be easily calculated since the concentrations at equilibrium are given.the calculation shows the value of Kc for the reversible reaction and forward reaction
Educated Guess Here!
Since Br-80 does not exist, maybe that means Br-79 or Br-81 have very unequal abundances. For example, Br-79 may have 75% abundance whereas Br-81 may have 25% abundance.
Answer:
Explanation:
The first reaction is oxidation of Mn to Mn²⁺ with HNO₃:
(4H⁺ + NO₃⁻ + 3e⁻ → NO + 2H₂O) x2
(Mn → Mn²⁺ + 2e⁻) x3
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(1) 3Mn + 8H⁺ + 2NO₃⁻ → 3Mn²⁺ + 2NO + 4H₂O
The oxidation to MnO₄⁻ with IO₄⁻ is:
(2e⁻ + 2H⁺ + IO₄⁻ → IO₃⁻ + H₂O) x5
(Mn²⁺ + 4 H₂O → MnO₄⁻ + 8H⁺ + 5e⁻) x2
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(2) 2Mn²⁺ + 5IO₄⁻ + 3H₂O → 2MnO₄⁻ + 5IO₃⁻ + 6H⁺
Explanations:- The shape of the molecule depends on bonding groups and lone pair of electrons present in the central atom. We do the sum of these bonding groups and lone pair of electrons for the shape of the molecule. The presence of lone pair of electrons affects the shape (molecular geometry) of the molecule.
For example, methane is tetrahedral as four hydrogen atoms are bonded to carbon and there is no lone pair of electrons present on C. Here, the sum of bonding groups and lone pairs is 4.
On the other hands, in water, two H atoms are bonded to the central oxygen atom and also there are two lone pair of electrons present on oxygen atom. The sum is also 4 here but the molecular geometry is bent. The difference in geometries of these two molecules is because of the repulsion between the two lone pairs present on oxygen atom.
If we take an example of boron hydride then three H atoms are bonded to B and there is no lone pair of electrons present on B. The sum is 3 and so it's shape is trigonal planar.
So, the number of bonded atoms as well as the number of lone pairs present on the central atom decides the shape of the molecule.
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