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Ronch [10]
3 years ago
14

Plz help! Gonna need to turn it soon

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
3 0

Answer:

C - 13*

Step-by-step explanation:

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Find five consecutive integers such that the sum of the first and 5 times the third is equal to 41 less than 3 times the sum of
bogdanovich [222]

Answer:

see below

Step-by-step explanation:

We'll cal the first integer x and then the rest of them will be x + 1, x + 2, x + 3 and x + 4. We can write x + 5(x + 2) = 3(x + 1 + x + 3 + x + 4) - 41.

x + 5x + 10 = 3(3x + 8) - 41

6x + 10 = 9x + 24 - 41

6x + 10 = 9x - 17

3x = 27

x = 9

The numbers are 9, 10, 11, 12, 13.

6 0
3 years ago
I need help asap please!
kupik [55]

Answer is in The picture attached. Hope it helps!

8 0
3 years ago
Select the points that is a solution
RoseWind [281]

The red area is the one which solves the system. In fact, we want the area which below both the parabola and the line (since the inequality features a \leq sign.


So, the point (1,1) is below the line but above the parabola (blue area), so it is not a solution.


The point (2,2) is above both the line and the parabola (white area), so it is not a solution.


The point (-1,0) is below both the line and the parabola (red area), so it is a solution.


So, the point (4,1) is below the parabola but above the line (green area), so it is not a solution.

8 0
3 years ago
What is 36/ 40 reduced its simplest form
trapecia [35]
36/40 reduced down to the simplest form would be 9/10. hope this helps!!

3 0
3 years ago
Read 2 more answers
Divide.<br> Write your answer in simplest form.<br> 2/5 divided by 2/3
Elena-2011 [213]

Answer:

3/5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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