QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
Answer:312cm. Squared I think
Step-by-step explanation:
Answer:
it is detailed solution. please mark brainlest.
Thank you have a nice day
Kulay, there is no such thing as a "step by step answer" here. You seem to want a "step by step solution."
I must assume that by 4/5 you actually meant (4/5) and that by 2/3 you meant (2/3). Then your equation becomes:
(4/5)w - 12 = (2/3)w.
The LCD here is 5*3, or 15, so mult. every term by 15:
12w - 180 = 10w.
Add 180 to both sides, obtaining 12 w - 180 + 180 = 10w + 180.
Then 12w = 10w + 180. Simplifying, 2w = 180. What is w?
