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2 years ago

A rectangle prism is shown below. What is the volume of the prism?

Mathematics

1 answer:

8_murik_8 [283]2 years ago

8 0

I can help with the formula just do the math on a calculator you multiply length x width x height

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Catherine needs to sell boxes of cookies as a fundraiser for a team. She starts with 135 boxes and begins selling at a constant

gtnhenbr [62]

Start at (0, 135) and work your way down 15 and over one each time. Your next point would be (1, 120)

8 0

3 years ago

Read 2 more answers

A regular hexagon is shown.

zhuklara [117]

The central angle of the hexagon is equal to 60º.

Therefore, the trigonometric relationship for the radius is given by:

$cos (30) = \frac{a}{c}$

Where,

a: apothema of the hexagon

c: Hexagon radius.

Clearing the radio we have:

$c = \frac{a}{cos (30)}$

Substituting values:

$c = \frac{12}{cos (30)} c = 13.85$

Rounding to the nearest whole number we have:

$c = 14 in$

Answer:

The measure of the radius, c, rounded to the nearest inch is:

C. 14 in.

7 0

3 years ago

Read 2 more answers

-5x^2-6=-4x using the Quadratic Formula.

a_sh-v [17]

Answer:

Step-by-step explanation:

-5x² - 6 = -4x

-5x² + 4x - 6 = 0

a = -5 ; b = 4 ; c = -6

Discriminant = b² - 4ac

= 4² - 4*(-5)*(-6)

= 16 - 120

= -104

roots = $\dfrac{-b+\sqrt{D}}{2a} \ ; \ \dfrac{-b-\sqrt{D}}{2a}$

$=\dfrac{-4+\sqrt{-104}}{2*(-5)};\dfrac{-4-\sqrt{-104}}{2*(-5)}\\\\=\dfrac{-4+2i\sqrt{26}}{-10} ; \dfrac{-4-2i\sqrt{26}}{-10}\\\\=\dfrac{(-2)[2-i\sqrt{26}]}{-10} \ ; \ \dfrac{(-2)[2+i\sqrt{26}]}{-10}\\\\=\dfrac{2-i\sqrt{26}}{5} \ ; \ \dfrac{2+i\sqrt{26}}{5}$

5 0

3 years ago

You are planning on purchasing a new car and have your eye on a specific model. You know that new car prices are projected to in

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

Cost of the car in "n" years=25000*(1+0.05)^n

Cost of the car in 2 years=25000*(1+0.05)^2=25000*(1.05)^2=27562.5

5 0

3 years ago

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.

3 0

3 years ago