C. coil suspended by bearings.
<span>but im not 100% sure</span>
Nope. It's called 'centripetal' acceleration. The force that created it MAY be gravitational, but it doesn't have to be. For things on the surface of the Earth moving in circles, it's never gravity.
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
)
Similarly;
However; the relative difference is:
![\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Chat%20%7Bk_a%7D%20-%20%5Chat%20%7Bk_b%7D%7D%7B%5Chat%20%7Bk_a%7D%20%7D%3D%20%5Cdfrac%7BE_a%20-E_a%20%2B%20%5Cdfrac%7B%5Csigma%7D%7B2%20%5Cvarepsilon_o%20%20%5CBig%5B1%20-%20%5Cdfrac%7B2.0%20%5C%20R%7D%7B%5Csqrt%7B%282.0%20%5C%20R%29%5E2%20%2B%20%28%5Cdfrac%7BR%7D%7B2%7D%29%5E2%7D%7D%20%5CBig%5D%20%7D%20%7D%20%7B%20%5Cdfrac%7B%5Csigma%7D%7B2%20%5Cvarepsilon_o%20%5CBig%20%5B%201%20-%20%5Cdfrac%7B2.0%20%5C%20R%7D%7B%5Csqrt%7B%20%282.0%20%5C%20R%29%5E2%20%2B%20%28R%29%5E2%7D%7D%20%5CBig%5D%20%7D%7D)
