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3 years ago

A steel rod has a length of 0.2 cm at 30 degrees C, what will be its length at 60 degrees C?

Physics

1 answer:

maks197457 [2]3 years ago

5 0

Answer:

2.00072 mm

Explanation:

So, we just have to calculate 2 mm x (1 + 0.36 x 10⁻³) = 2 mm + 0.00072 mm = 2.00072 mm

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During each cycle of operation a refrigerator absorbs 56 cal from the freezer compartment and expels 81 cal tothe room. If one c

Alexandra [31]

Answer:

138.18 minutes

Explanation:

$L_v$ = Latent heat of water at 0°C = 80 cal/g

m = Mass of water = 570 g

Heat removed for freezing

$Q=mL_v\\\Rightarrow Q=570\times 80\\\Rightarrow Q=45600\ cal$

Let N be the number of cycles and each cycle removes 56 cal from the freezer.

So,

$55\times N=45600\\\Rightarrow N=\frac{45600}{55}$

Each cycle takes 10 seconds so the total time would be

$\frac{45600}{55}\times \frac{10}{60}=138.18\ minutes$

The total time taken to freeze 138.18 minutes

6 0

3 years ago

According to the Law of Reflection, the angle of incidence the angle of reflection. O A. is greater than B. is less than C. equa

Amanda [17]

Answer:

C. Equals

Explanation:

Law of reflection Equals the angle of incidence

8 0

3 years ago

Pendulum A has a bob of mass m hung from the string of length L; pendulum B is identical to A except its bob has the length 2L.

GenaCL600 [577]

Answer:

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

Explanation:

For pendulum A: Length = L and gravity = g

The frequency of pendulum A is given by

$f = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$

Here, f is the frequency, L be the length

$f_{A} = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$ ... (1)

For pendulum B: Length = 2L, gravity = g

The frequency of pendulum B is given by

$f_{B} = \frac{1}{2\pi }\sqrt{\frac{g}{2L}}$ .... (2)

Divide equation (1) by (2)

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

5 0

3 years ago

Define refraction of light

Elza [17]

Answer:

Refraction is the slowing down of light waves as they pass into a different medium and speeding as they pass out.

hope it helps. plz mark me as brainliest.

6 0

3 years ago

A car slows down uniformly from a speed of 22 m/s to rest in 4.0 seconds. How far did it travel in that time

krek1111 [17]

Answer:

$\boxed{\sf Distance \ travelled = 44 \ m}$

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

$\boxed{ \bold{s = (\frac{v + u}{2} )t}}$

By substituting value of v, u & t in the equation we get:

$\sf \implies s = ( \frac{0 + 22}{2} ) \times 4 \\ \\ \sf \implies s = \frac{22}{2} \times 4 \\ \\ \sf \implies s = 11 \times 4 \\ \\ \sf \implies s = 44 \: m$

$\therefore$

Distance travelled by car (s) = 44 m

4 0

4 years ago