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Gre4nikov [31]
3 years ago
12

What are two ways in which ultrasound technology produces images

Physics
1 answer:
arsen [322]3 years ago
6 0
Fetal and ophthalmic
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Given the Earth's density as 5.5 g/cm3 and the Moon's density as 3.34 g/cm3, determine the Roche limit for the Moon orbiting the
Assoli18 [71]

Answer:

The Roche limit for the Moon orbiting the Earth is 2.86 times radius of Earth

Explanation:

The nearest distance between the planet and its satellite at where the planets gravitational pull does not torn apart the planets satellite is known as Roche limit.

The relation to determine Roche limit is:

Roche\ limit=2.423\times R_{P}\times\sqrt[3]{\frac{D_{P} }{D_{M} } }     ....(1)

Here R_{P} is radius of planet and D_{P}\ and\ D_{M} are density of planet and moon respectively.

According to the problem,

Density of Earth,D_{P} = 5.5 g/cm³

Density of Moon,D_{M} = 3.34 g/cm³

Consider R_{E} be the radius of the Earth.

Substitute the suitable values in the equation (1).

Roche\ limit=2.423\times R_{E}\times\sqrt[3]{\frac{5.5 }{3.34 } }

Roche\ limit= 2.86R_{P}

8 0
3 years ago
Chance drives his scooter 7km north he stops for lunch and then drives 5km East to his friend house what distance did he cover
Katena32 [7]

Answer:12km

Explanation:

7km+5km=12km

6 0
3 years ago
What is a metallic bond and how does it hold metals together?
Marysya12 [62]

Answer:

Force that holds atoms together in a metallic substance.

Explanation:

Hope this helps? C:

~Chiena

4 0
2 years ago
What are Base Quantities ?​
Norma-Jean [14]

Answer:

<em>physical quantities that cannot be defined in terms of other quantities.</em>

<em>Examples</em><em>:</em><em> </em><em>Length - meter (m)Time - second (s)Amount of substance - mole (mole)Electric current - ampere (A)Temperature - kelvin (K)Luminous intensity - candela (cd)Mass - kilogram (kg)</em>

6 0
3 years ago
Read 2 more answers
At what height above the ground must a mass of 10 kg be to have a potential energy equal in value to the kinetic energy possesse
Paladinen [302]

Answer:

20 m

Explanation:

We'll begin by calculating the kinetic energy of the mass. This can be obtained as follow:

Mass (m) = 10 kg

Velocity (v) = 20 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 10 × 20²

KE = 5 × 400

KE = 2000 J

Finally, we shall the height to which the mass must be located in order to have potential energy that is the same as the kinetic energy. This can be obtained as follow:

Mass (m) = 10 kg

Acceleration due to gravity (g) = 10 m/s²

Potential energy (PE) = Kinetic energy (KE) = 2000 J

Height (h) =..?

PE = mgh

2000 = 10 × 10 × h

2000 = 100 × h

Divide both side by 100

h = 2000 / 100

h = 20 m

Thus, the object must be located at a height of 20 m in order to have potential energy that is the same as the kinetic energy.

5 0
3 years ago
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