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3 years ago

The pointer of an analog meter is connected to a

Physics

2 answers:

dangina [55]3 years ago

8 0

C. coil suspended by bearings.
<span>but im not 100% sure</span>

Rom4ik [11]3 years ago

5 0

Answer: the correct answer is c coil suspended by bearings.

Explanation: this is so that whenever the coil detect a parameter to be measured say current voltage or resistance it energizes and the bearings moves accordingly to indicate the corresponding reading

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On what principle does a bottle opener work

Vsevolod [243]

Answer:

Bottle opener works on a fulcrum.

Explanation:

A bottle opener is a second-class lever because the pivot point is at one end of the opener and the load is in the middle.

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3 years ago

Two 0.50 g spheres are charged equally and placed 2.5 cm apart. When released, they begin to accelerate at 170 m/s^2 .What is th

vitfil [10]

Answer:

$q=7.65*10^{-8}C$

Explanation:

Using Newton's second law, we calculate the magnitude of the electric force between the spheres:

$F=ma\\F=0.5*10^{-3}kg(170\frac{m}{s^2})\\F=0.085N$

The magnitude of the charge in both spheres is the same. So, we calculate the charge, using Coulomb's law:

$F=\frac{kq^2}{d^2}\\q=\sqrt\frac{Fd^2}{k}\\q=\sqrt\frac{(0.085N)(2.5*10^{-2}m)^2}{8.99*10^9\frac{N\cdot m^2}{C^2}}\\q=7.65*10^{-8}C$

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3 years ago

Is there like an actual definition for momentum?

krok68 [10]

Yes there is.

Momentum of an object is (its mass) times (its speed) .

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3 years ago

Which of the following words BEST describes scientists’ current knowledge about the universe?

Vilka [71]

Answer:

your answer is changing

Explanation:

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3 years ago

A pitcher throws a baseball with a mass of 143 g horizontally at a speed of 38.8 m/s (87 mi/h). The hitter's bat is in contact w

SIZIF [17.4K]

Answer:

F = −10093.41 N

Explanation:

Given that,

Mass of a baseball, m = 143 g = 0.143 kg

Initial speed of the baseball, u = +38.8 m/s

The hitter's bat is in contact with the ball for 1.20 ms and then travels straight back to the pitcher's mound at a speed of 45.9 m/s, v = -45.9 m/s

We need to find the average force exerted on the ball by the bat. So, Force is given by :

$F=ma$

a is acceleration

$F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.143\times (-45.9-(38.8))}{1.2\times 10^{-3}}\\\\F=-10093.41\ N$

So, the average force exerted on the ball by the bat has a magnitude of 10093.41 N.

8 0

3 years ago