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erik [133]
3 years ago
12

Estimate the solution to the system of equations.

Mathematics
1 answer:
Georgia [21]3 years ago
5 0

Answer:

<em>x = 4 / 3, y = 7 / 3</em>

Step-by-step explanation:

We are given the following system of equations;

{ 7x - y = 7,      ⇒        Let us multiply the first equation by 2,

x + 2y = 6 }

2 * ( 7x - y = 7 )  ⇒  14x - 2y = 14  ⇒  Now add the two equations

+ x + 2y = 6           + x  + 2y = 6                          

14x + x = 14 + 6 ⇒ Simplify

15x = 20,

<em>x = 4 / 3</em> ⇒ Now substitute this value of x into the first equation to solve for the value of y,

7 * ( 4 / 3 ) - y = 7 ⇒ Simplify,

28 / 3 - y = 7,

y = 7 / 3

<em>Solution; x = 4 / 3, y = 7 / 3</em>

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What is the approximate distance from the origin to the point (3, −4, 5)? Round to the nearest unit. 4 units 7 units 8 units 9 u
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Answer:

Option B is correct.

Step-by-step explanation:

The distance formula used is:

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}

We need to find distance between origin and other point (3,-4,5)

Origin is: (0,0,0)

x₁ = 0, y₁ = 0, z₁ =0 and x₂= 3, y₂= -4 and z₂ = 5

Putting values in the distance formula we get:

d=\sqrt{(3-0)^2+(-4+0)^2+(5-0)^2}\\d=\sqrt{(3)^2+(-4)^2+(5)^2}\\d=\sqrt{9+16+25}\\d=\sqrt{50}\\d=7

The Distance from the origin to the point (3, −4, 5) is 7 units.

Option B is correct.

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Read 2 more answers
-x + 2y = 3<br> 2x – 3y = -6
s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>Equating</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

4 0
3 years ago
James took a math quiz in which he earned 1 point for every correct answer and lost 0.5 points for every incorrect answer.James
Nuetrik [128]

Answer:

9

Step-by-step explanation:

6x0.5=3-12=9

4 0
3 years ago
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