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EleoNora [17]
3 years ago
7

Based on the scores in the chart below which restaurant is the best choice for the dinner tonight and why

Mathematics
1 answer:
masha68 [24]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Ku's since it has the highest score with +12

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HELP PLZ . Enter the slope of the line .
Korolek [52]
I hope this helps you



slope=y2-y1/x2-x1



slope= -3-(-4)/0-2


slope=-3+4/-2


slope= -1/2
4 0
3 years ago
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In a certain soccer tournament you are playing once with each of the other nine teams. In every match you get 3 points if you wi
bixtya [17]

Answer:

0.430625=0.431

Step-by-step explanation:

Answer:

0.430625 = 0.431

Step-by-step explanation:

Let W represent winning, D represent a draw and L represent a loss.

12+ points can be garnered in each of the following ways.

6W 0D 0L

5W 1D 0L

5W 0D 1L

4W 2D 0L

4W 1D 1L

4W 0D 2L

3W 3D 0L

The probability of getting 12+ points is the sum of all these 7 probabilities.

Knowing that P(W) = 0.5

P(D) = 0.1

P(L) = 0.4

P(6W 0D 0L) = [6!/(6!0!0!)] 0.5⁶ 0.1⁰ 0.4⁰ = 0.015625

P(5W 1D 0L) = [6!/(5!1!0!)] 0.5⁵ 0.1¹ 0.4⁰ = 0.01875

P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075

P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375

P(4W 1D 1L) = [6!/(4!1!1!)] 0.5⁴ 0.1¹ 0.4¹ = 0.075

P(4W 0D 2L) = [6!/(4!0!2!)] 0.5⁴ 0.1⁰ 0.4² = 0.15

P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025

The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625

Read more on Brainly.com - brainly.com/question/14850440#readmore

4 0
3 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5). Describe the ste
olga_2 [115]
1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.

2. So f(x)=(x-a)^{3}

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions: 
 
f(x)=b(x-a)^{3}

4. Now, f(0)=-5 so  -5=f(0)=b(0-a)^{3}=b(-a) ^{3}=-ba ^{3}

-5=-ba ^{3}

5=ba ^{3}

b= \frac{5}{ a^{3} }

5. the function is f(x)=\frac{5}{ a^{3} }(x-a)^{3} where a can be any real number except 0
7 0
3 years ago
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Helppp!!!! please!!!
Vitek1552 [10]

Answer:

d. 15 square yard

Step-by-step explanation:

area \: of \: shape \\  =  \frac{1}{2}  \times base \times height \\  \\  =  \frac{1}{2}  \times 10 \times 3 \\  \\  =  \frac{1}{2}  \times 30 \\  \\  = 15 \:  {yd}^{2}

4 0
3 years ago
Read 2 more answers
An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen
devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = \frac{\sum X}{n} = 441

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 14.34

            n = sample size = 16

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<em />

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X -2.131 \times {\frac{s}{\sqrt{n} } } , \bar X +2.131 \times {\frac{s}{\sqrt{n} } } ]

                                      = [ 441-2.131 \times {\frac{14.34}{\sqrt{16} } } , 441+2.131 \times {\frac{14.34}{\sqrt{16} } } ]

                                      = [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0
3 years ago
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