Help!!!!! please!!!!!

Mathematics

2 answers:

ASHA 777 [7]3 years ago

4 0

Answer:

Solution,

Diameter (d)= 32 in

Radius (r)= 32/2= 16 in

Surface area of sphere:

$4\pi {r}^{2} \\ = 4 \times \pi \times {(16)}^{2} \\ = 4 \times \pi \times 256 \\ = 1024\pi \\ = 1024 \times 3.142 \\ = 3217.108 \: {in}^{2}$

Hope this helps...

Good luck on your assignment...

AlladinOne [14]3 years ago

3 0

Answer:

Step-by-step explanation:

Diameter = 32 in

r = 32/2 = 16 in

Surface area of sphere = 4πr²

= 4 * 3.142 * 16 * 16

= 3217.408

= 3217 in²

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Enter the explicit rule for the sequence

Softa [21]

Let's take a look at the first few numbers in the sequence based on the given rule:

$a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)$

Inspecting this pattern it seems like the power $\frac{1}{4}$ is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be $\big(\frac{1}{4} \big)^{n-1}$ . We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

$a_n=6\big( \frac{1}{4} \big)^{n-1}$

Where $a_n$ is the nth number in our sequence.