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RUDIKE [14]
3 years ago
10

Need help with this question, much appreciated.

Mathematics
1 answer:
taurus [48]3 years ago
8 0

Answer:

75 degrees

Step-by-step explanation:

1. Find angle J.

The outside angle and angle J are supplementary, which means they add up to 180 degrees.

180 - 130 = 50.

So angle J is 50 degrees.

2. The angles in a triangle add up to 180. Add up angles J and K and subtract that from 180

50 +65 = 105

180- 105 = 75

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Can you help me solve these questions....please and thank you!
FromTheMoon [43]
42)
prime numbers are 41, 43, 47
answer
F. 3

35)
36 colored
faction 36/60 = 18/30 = 6/10 = 3/5

faction not equivalent to is  8/20

answer is C. 8/20

11)
answer is D. 18.21

cause 18.21 > 17.06 and 18.21 < 18.307



5 0
4 years ago
Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach
jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}

8 0
3 years ago
the summer camps had a field trip from the campus to fragrance hill. they traveled at an average speed of 65km/h in the first tw
sergejj [24]

Answer:

I took them a total of 5 hours

Step-by-step explanation:

First you multiply 65 by 2 because of the first two hours

Then you subtract 130 out of 364 to get 234, those were the first two hours

The next hours you simply divide 234/78, which is 3

3 + 2 = 5 hours

4 0
3 years ago
Solve R=M + B, for B.
musickatia [10]

Answer:

B = R - M

Step-by-step explanation:

1. R = M + B       Subtract M

2.  R - M = B

8 0
3 years ago
two dice are rolled, given that the total showing on the two dice is 7, find the probability that one of the dice shows the numb
kipiarov [429]

Answer:

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is 6/36 = 1/6.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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