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san4es73 [151]
4 years ago
10

  complete and balance the following reactions ?   uo2+ +cr o^2- 7 ـــــــــــــــــــــ uo2+ +cr3+

Chemistry
2 answers:
OlgaM077 [116]4 years ago
6 0
The answer will be Fe. Hope it help!
ivanzaharov [21]4 years ago
3 0
In order to <span>complete and balance the following reactions, you should add a Fe into it. So it will look like  uo2+ +cr o^2- 7 ـــــــــــــــــــــ uo2+ +cr3+Fe. The answer to the following given statement or missing answer is Fe. </span>
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If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc
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Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

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moles of NaOH = \frac{57.4\times 1000g}{40g/mol}=1435moles

moles of HF = \frac{57.4\times 1000g}{20g/mol}=2870moles

As 1 mole of Al_2O_3 reacts with 6 moles of NaOH

166 moles of  Al_2O_3 reacts with = \frac{6}{1}\times 166=996 moles of NaOH

As 1 mole of Al_2O_3 reacts with 12 moles of HF

166 moles of  Al_2O_3 reacts with = \frac{12}{1}\times 166=1992 moles of HF

Thus Al_2O_3 is the limiting reagent.

As 1 mole of Al_2O_3 produces = 2 moles of cryolite

166 moles of  Al_2O_3 reacts with = \frac{2}{1}\times 166=332 moles of cryolite

Mass of cryolite (Na_3AlF_6) = moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg

Thus 69.72 kg of cryolite will be produced.

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