Answer:
Balancing Nuclear Equations
To balance a nuclear equation, the mass number and atomic numbers of all particles on either side of the arrow must be equal.
Explanation:
follows:
6
3
Li
 
+
 
 
2
1
H
→
 
4
2
He
 
+
 
?
To balance the equation above for mass, charge, and mass number, the second nucleus on the right side must have atomic number 2 and mass number 4; it is therefore also helium-4. The complete equation therefore reads:
6
3
Li
 
+
 
 
2
1
H
→
 
4
2
He
 
 
+
 
 
4
2
He
Or, more simply:
6
3
Li
 
+
 
 
2
1
H
→
2
 
4
2
He
image
Lithium-6 plus deuterium gives two helium-4s.: The visual representation of the equation we used as an example.
Compact
 
        
             
        
        
        
D. the student's conclusion shows experimental bias
        
             
        
        
        
Answer: 1.  
 
2. 3 moles of  : 2 moles of
 : 2 moles of 
3. 0.33 moles of  : 0.92 moles of
 : 0.92 moles of 
4.  is the limiting reagent and
 is the limiting reagent and  is the excess reagent.
 is the excess reagent.
5. Theoretical yield of  is 29.3 g
 is 29.3 g 
Explanation:
To calculate the moles :
 
    
 

The balanced chemical equation is:
 
  
According to stoichiometry :
3 moles of  require = 2 moles of
 require = 2 moles of  
Thus 0.33 moles of  will require=
 will require= of
  of  
Thus  is the limiting reagent as it limits the formation of product and
 is the limiting reagent as it limits the formation of product and  is the excess reagent.
 is the excess reagent.
As 3 moles of  give = 2 moles of
 give = 2 moles of  
Thus 0.33 moles of  give =
 give = of
  of  
Theoretical yield of  
Thus 29.3 g of aluminium chloride is formed.
 
        
             
        
        
        
The pressure is a result of the motion of particles
        
                    
             
        
        
        
Answer: A) This reaction will be spontaneous only at high temperatures
Explanation:
 = +ve, reaction is non spontaneous
= +ve, reaction is non spontaneous
 = -ve, reaction is spontaneous
= -ve, reaction is spontaneous
 = 0, reaction is in equilibrium
= 0, reaction is in equilibrium
Using Gibbs Helmholtz equation:
 
Given :  
 
 
 
Thus the value of   is negative and spontaneous when temperature is high.
  is negative and spontaneous when temperature is high.