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aleksklad [387]
3 years ago
14

How many elements are in C5H4O2S

Chemistry
1 answer:
elena-s [515]3 years ago
8 0

Answer:

4 elements

Explanation:

The four elements would be:

C-Carbon

H-Hydrogen

O-Oxygen

S-Sulfur

Hope this helps :)

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Which scenario suggest that the results of an experiment are reliable
ale4655 [162]
What is a reliable scientific experiment?experiment, experimentation, experiments, reliable scientific experiment, science, scientific, scientific experiment, scientific experiments, scientific method

Now that the atheists have taken over science and have de-valued and discouraged experimentation I’ll try to re-value experimentation and encourage experimentation again like how it use to be prior to atheists taking over science in the late 1960s and early 1970s.

Why have atheists done this? It’s because experimentation gives us data that reflects reality, and often reality behaves very differently from how scientists want to think it does. Modern day atheist scientists want to find data that matches into their incredulity and mathematical models, not data that necessarily reflects how reality works.

Remember, experimental data is used to verify the accuracy of mathematical models, not the other way around like many modern day scientists think.

So I’ve come up with the basic properties of a highly reliable scientific experiment.

The Properties of a Reliable Scientific Experiment:

– Repeatability:  This means that the exact same results of the experiment are duplicated over and over again (when following the exact same set of systematic procedures). If the results of an experiment can be repeated over and over again yielding the exact same effect when following the exact same set of procedures, then the results of the experiment cannot be denied (although the results can possibly be interpreted differently). If your experiment only yields a certain result one time or a few times or in a non-repeatable condition then the experiment is not useful or scientific.

– Controls: Since correlation is not causation it’s important to have controls (if possible) to determine what’s causing certain results in an experiment. Having controls eliminates certain variables causing certain effects in the results of an experiment.

A simple example can be seen with determining which fertilizer is best for plant growth. In order to create a scientific experiment you would have to keep all the variables the same except for the fertlizer (these are the controls). Like the plant type, the amount of water each day, the time watered, the exposure to light, etc…

Without having control variables it would be unclear as to what’s causing the results in the experiment.

– <span>Not Relying on Subjective Users: </span> This ties into repeatability and means that the experiment doesn’t rely upon any subjective methodology, like only working if special users participate, a subjective bias or anything like that. Take for instance remote viewing experiments that only work if specially trained remote viewers participate. Since they would only work if special users participate it doesn’t give us any reliable repeatable data that’s useful in science.


So i hope this helps you and please makes this the brainly-est  answer...thanks 

4 0
3 years ago
For IR radiation with û = 1,130 cm 1, v=__THz
Dmitry [639]

<u>Answer:</u> The frequency of the radiation is 33.9 THz

<u>Explanation:</u>

We are given:

Wave number of the radiation, \bar{\nu}=1130cm^{-1}

Wave number is defined as the number of wavelengths per unit length.

Mathematically,

\bar{\nu}=\frac{1}{\lambda}

where,

\bar{\nu} = wave number = 1130cm^{-1}

\lambda = wavelength of the radiation = ?

Putting values in above equation, we get:

1130cm^{-1}=\farc{1}{\lambda}\\\\\lambda=\frac{1}{1130cm^{-1}}=8.850\times 10^{-4}cm

Converting this into meters, we use the conversion factor:

1 m = 100 cm

So, 8.850\times 10^{-4}cm=8.850\times 10^{-4}\times 10^{-2}=8.850\times 10^{-6}m

  • The relation between frequency and wavelength is given as:

\nu=\frac{c}{\lambda}

where,

c = the speed of light = 3\times 10^8m/s

\nu = frequency of the radiation = ?

Putting values in above equation, we get:

\nu=\frac{3\times 10^8m/s}{8.850\times 10^{-4}m}

\nu=0.339\times 10^{14}Hz

Converting this into tera Hertz, we use the conversion factor:

1THz=1\times 10^{12}Hz

So, 0.339\times 10^{14}Hz\times \frac{1THz}{1\times 10^{12}Hz}=33.9THz

Hence, the frequency of the radiation is 33.9 THz

7 0
3 years ago
Help asap!
Anton [14]
E i believe so not sure
6 0
3 years ago
John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bottle,
enot [183]

One can solve the problem by using the law of conservation of momentum. The total momentum prior to the collision must be equivalent to the total momentum after the collision, so we have:

m1v1 + m2v2 = m1v1 + m2v2

Here, m1 is 0.4 Kg that is the mass of the ball, u1 is 18 m/s that is the initial velocity of the ball, m2 is 0.2 Kg that is the mass of the bottle, and u2 is 0 that is the initial velocity of the bottle.

v1 is the final velocity of the ball, which is to be determined, and v2 is 25 m/s that is the final velocity of the bottle.

Substituting and rearranging the equation, one can find the final velocity of the ball:

v1 = m1u1 - m2v2 / m1 = (0.4 kg) (18 m/s) - (0.2 Kg) (25 m/s) / 0.4 Kg = 5.5 m/s.

5 0
3 years ago
Read 2 more answers
If a force of 1.4N is applied to a block with a mass of 7kg, what is the acceleration of the block in meters per second squared?
Anton [14]

Answer:

<h2>0.2 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{1.4}{7} =  \frac{1}{5}   \\

We have the final answer as

<h3>0.2 m/s²</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
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