Answer:
Age of son = 6 years
Age of man = 5×6 = 30 years
Step-by-step explanation:
<u>GIVEN :-</u>
- A man is 5 times as old as his son. (In Present)
- 4 years ago , the man was 13 times as old as his son
<u>TO FIND :-</u>
- The present ages of the man & his son.
<u>SOLUTION :-</u>
Let the present age of son be 'x'.
⇒ Present age of man = 5x
4 years ago ,
Age of son = (Present age of son) - 4 = x - 4
Age of man = (Present age of man) - 4 = 5x - 4
The man was thirteen times as old as his son. So,
Now , solve the equation.
- Open the brackets in R.H.S.
- Take 5x to R.H.S. and -52 to L.H.S. Also , take care of their signs because they are getting displaced from L.H.S. to R.H.S. or vice-versa.
- Divide both the sides by 8
<u>CONCLUSION :-</u>
Age of son = 6 years
Age of man = 5×6 = 30 years
58-180=122 x=122 hope this helps have a nice nite!
Answer:
que cantidad de ingereses genera un prestamo de 10000 dolares que se contrato el 1 de agosto de 2017 para reembolsarse el 1 de agosto de 2020, con interes simple del 10 % anua
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
x = 4
Step-by-step explanation:
we know that 72 and (2x + 10) add up to 90
90-72 = 18
(2x + 10) = 18
2x = 8
x = 4
