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Andrej [43]
3 years ago
13

4(2+3c)= 56 Solve each equation.

Mathematics
1 answer:
iris [78.8K]3 years ago
8 0
Distribute the 4.

8 + 12c = 56

Subtract 8.

12c = 48

c = 4
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laila [671]
Hello,

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==>7x=65
==> x =9+2/7

Answser A
8 0
3 years ago
Please solve x^2-8x=8
Varvara68 [4.7K]

Answer:4^2-(8x1)=8

Step-by-step explanation:

3 0
3 years ago
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LOL 3 more to gooo . find the value of x
garri49 [273]

Answer:

17

Step-by-step explanation:

These two angles add up to 180, so we can set up an equation. 5x-23+7x-1=180. Now we combine like variables, getting 12x-23-1=180. We add 23 to both sides, and get 12x-1=203. Then we add 1 to both sides, getting 12x=204. Finally we divide by 12 on both sides, with our result as x=17.

8 0
3 years ago
URGENT please help!!! I need a explanation please!! You own a restaurant and can reopen as long as people seated at a table are
hram777 [196]

Answer:

1) Maximum number of tables that can be kept in the dinning room is 10 tables

2)The maximum number of customers, given 6 people per table is 60 customers

Step-by-step explanation:

The parameters given are;

Distance between people seated at different tables = 6 ft

Dimension of table = 2 m by 1.5 m

Number of people at a table = 6 people

Dimension of dinning;

Width = 12 m

Length = 20 m

Dimension of entrance;

Width = 20/21*30  m

Length = 10 m

With 6 meters between tables and a table with of 1.5, we have for the arrangement in the question;

3 tables = 4.5 m

Distance between = 2 × 6 = 12

4.5 + 12 = 16 m (More room required)

With two tables, we have;

Width of tables = 2×1.5 = 3 m

Distance between = 6 m

Dining room width required = 3 + 6 = 9 m

Therefore, the maximum tables in each row = 2

Given that the dining room area extends to the entrance area, total length = 30 m.

With 4 tables we have;

Length = 4 × 2 + 6 × 3 = 26

While on the entrance side of the dinning room area which is 20 m, we have 3 tables;

Length = 3 × 2 + 6 × 2 = 18

Therefore, both arrangements are acceptable;

Just on entering by the right the length = 20/21×30 m

Therefore, with 3 tables will required number due to proximity wit the door and tables arranged along the right wall of the dinning

1) Maximum number of tables that can be kept in the dinning room = 4 + 3 + 3 = 10 tables

2)The maximum number of customers, given 6 people per table = 6×10 = 60 customers.

4 0
3 years ago
Can I see how long division works on these? pls no sketchy links
alexandr1967 [171]

Answer:

Step-by-step explanation:

11) First write in decreasing exponential terms and fill in blanks with zeros.

Our goal is to eliminate all term in the dividend by subtraction

          ________________

2v - 2 |  2v³ - 16v² + 0v + 13

we see that 2v needs to be multiplied by 1v² to eliminate the first term

          <u>              v²                </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v²

multiply your estimate by your divisor and subtract from the dividend.

bring down the next term and repeat.

          <u>              v²    -7v       </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v

repeat again

<u />

          <u>              v²  -  7v  -  7 </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v + 13

                            <u>-(-14v + 14)</u>

                                          -1

and remainder gets put over the divisor and appended

v²  -  7v  -  7 - 1/(2v - 2)

13) Same process

          <u>                                      </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>              8a²                 </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

          <u>              8a² -    4a     </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                   -(-<u>20a² -   4a)</u>

                                -35a - 5

          <u>              8a² -    4a  - 7  </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                    -(<u>20a² -   4a)</u>

                                -35a - 5

                              -<u>(-35a - 7)</u>

                                           2

8a² - 4a - 7 + 2/(5a + 1)

5 0
3 years ago
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