D. X = 10
6x-20= 40
6x=40+20
6x=60
X=10
Answer:
B. 34.90°
Step-by-step explanation:
✔️First, find GF using Trigonometric function:
Reference angle = 58°
Adjacent length = GF
Hypotenuse = 6 cm
Apply CAH, thus:
Cos 58 = Adj/Hyp
Cos 58 = GF/6
GF = 6*Cos 58
GF = 3.17951558 ≈ 3.18 cm
✔️Find angle K using the Sine Rule:
Substitute
Multiply both sides by 3.18
K = 34.8618741° ≈ 34.90°
Answer=24 blue marbles and 3 red marbles
r=red marbles
b=blue marbles
b=3(r+5)
27=b+r
substitue b for '3(r+5)'
27=3(r+5)+r
27=3r+15+r
27=4r+15
subtract 15 from both sides
12=4r
divide both sides by 4
3=r
There are 3 red marbles
27=b+r
27=b+3
subtract 3 from both sides
24=b
There are 24 blue marbles
Answer:
At 25 = 6.8612mm
At 50 years = 5.422mm
Step-by-step explanation:
Equation,
d = 2.115Logₑa + 13.669
d = diameter of the pupil
a = number of years
Note : Logₑa = In a (check logarithmic rule)
d = 2.115Ina + 13.669
1. At 25 years,
d = -2.115In25 + 13.669
d = -2.115 × 3.2188 + 13.669
d = -6.807762 + 13.669
d = 6.8612mm
At 25 years, the pupil shrinks by 6.86mm
2. At 50 years,
d = -2.1158In50 + 13.669
d = -2.1158 * 3.912 + 13.669
d = -8.2770 + 13.699
d = 5.422mm
At 50 years, the pupil shirks by 5.422mm
To save this question, I had to plug in the values into the equation.
Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.
4028 mi 2< M is the expression you were looking for i think
