1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hoa [83]
3 years ago
5

Is g(x)=9+7x a linear equation

Mathematics
2 answers:
zalisa [80]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

A linear equation follows the y=mx+b equation. Your equation is g(x)= 7x+9 which follows the formula.

Dovator [93]3 years ago
4 0

Answer:

Yes.

Step-by-step explanation:

Option #1: Graph the equation. (you can search "y=9+7x")

Option #2: Look at the equation. Rewrite it as "y=7x+9". This follows the form of y=mx+b, which is the form of a linear equation.

You might be interested in
Triangle MNP is dilated according to the rule DO,1.5 (x,y)(1.5x, 1.5y) to create the image triangle M'N'P, which is not shown. W
scoray [572]

Answer: ?????????

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
Write as a product of two polynomials. <br><br> (x-y)^2-a(y-x)
Setler79 [48]

Answer:

\sf{(x-y)^2-a(y-x)} \\ = \sf{({x}^{2}  - 2xy +  {y}^{2} ) - (ay - ax)} \\

7 0
2 years ago
Read 2 more answers
Please help! (100 points!) look at the image :)
viva [34]

Answer:

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
Other questions:
  • 5m &gt; 20 how do I solve this??
    7·1 answer
  • Find the volume of the right circular cone that’s has the radius of 4 inches and height of 12 inches
    12·1 answer
  • 1.628 &gt; 1.63<br><br><br>I don’t understand math I’m sorry-
    15·1 answer
  • If someone could help with these questiones
    11·1 answer
  • John is 1.6 m tall. robbin is 156 cm tall what is the ratio of johns' height to robbins height?
    12·1 answer
  • Helppppppppppplszzzz
    5·2 answers
  • Michael is going back to school shopping to buy only jeans. He has 130 to spend. He found them on
    10·1 answer
  • Martin is seating people in the cars of a roller coaster. Each car can seat 8 people. Six of the roller coaster cars are yellow
    14·1 answer
  • When is the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx-7%7D%7Bx%5E2-4x-21%7D%20%3D%5Cfrac%7B1%7D%7Bx%2B3%7D" id="Tex
    11·1 answer
  • Somebody send me sum naughty...;)​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!