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3 years ago

Is g(x)=9+7x a linear equation

Mathematics

2 answers:

zalisa [80]3 years ago

7 0

Answer:

Yes

Step-by-step explanation:

A linear equation follows the y=mx+b equation. Your equation is g(x)= 7x+9 which follows the formula.

Dovator [93]3 years ago

4 0

Answer:

Yes.

Step-by-step explanation:

Option #1: Graph the equation. (you can search "y=9+7x")

Option #2: Look at the equation. Rewrite it as "y=7x+9". This follows the form of y=mx+b, which is the form of a linear equation.

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Colin invests £4000 into his bank account. He receives 5% per year simple interest. How much will Colin have after 3 years? Give

MakcuM [25]

Answer:

2750

Step-by-step explanation:

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2 years ago

Given x – 5 < One-fourth (y – 8)2, which graph represents the inequality?

Annette [7]

Step-by-step explanation:

x - 5 < 2 (y - 8) • 1/4

x - 5 < (y - 8) / 2

2 (x - 5) < y - 8

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3 years ago

Help me with this please!!

valina [46]

<h2><u>Given:</u><u>-</u></h2>

Points C = (-7,2) → $\sf{(X_1,Y_1)}$
D = (3,12) → $\sf{(X_2,Y_2)}$

The Midpoint of CD.

<h2><u>Required</u><u> </u><u>Response</u><u>:</u><u>-</u></h2>

Let,

Midpoint of CD be (x,y).

WKT,

$\boxed{\sf{(x,y) = \frac{X_1+X_2}{2},\frac{Y_1+Y_2}{2}}}$

$→\;{\sf{\frac{-7+3}{2},\frac{2+12}{2}}}$

$→\;{\sf{\frac{-4}{2},\frac{14}{2}}}$

$→\;{\sf{-2,7}}$

The Midpoint of CD ◕➜ $\Large{\red{\mathfrak{(-2,7)}}}$

Let,

The centre be O

Radius = CO & OD

Here, C = (-7,2) → $\sf{(X_1,Y_1)}$

O = (-2,7) → $\sf{(X_2,Y_2)}$

$\boxed{\sf{Distance = \sqrt{(X_2-X_1)²+(Y_2-Y_1)²}}}$

$→\;{\sf{\sqrt{(-2+7)²+(7-2)²}}}$

$→\;{\sf{\sqrt{5²+5²}}}$

$→\;{\sf{\sqrt{25+25}}}$

$→\;{\sf{\sqrt{50}}}$

$→\;{\sf{5√2 (or) 7.07}}$

Radius of Circle ◕➜ $\Large{\red{\mathfrak{7.07}}}$

<h2>Option D.</h2>

Hope It Helps You ✌️

3 0

2 years ago

Use a trigonometric identity to find the indicated value in the specified quadrant.

aleksandr82 [10.1K]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2782751

_______________

Cosine and secant functions are reciprocal, which means

$\mathsf{sec\,\theta=\dfrac{1}{cos\,\theta}}$

So, if $\mathsf{cos\,\theta=\dfrac{3}{8},}$ then

$\mathsf{sec\,\theta=\dfrac{1}{~\frac{3}{8}~}}\\\\\\
\mathsf{sec\,\theta=\dfrac{8}{3}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>cosine secant cos sec relation reciprocal trig trigonometry</em>

7 0

3 years ago

Solve for X : 8x + 3 = 2x

lys-0071 [83]

Answer:

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Step-by-step explanation:

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2 years ago