Answer:
<em><u>given </u></em><em><u>:</u></em><em><u>-</u></em>
<em><u>for </u></em><em><u>rectangular</u></em><em><u> </u></em><em><u>part:</u></em><em><u> length</u></em><em><u>=</u></em><em><u>1</u></em><em><u>2</u></em><em><u>i</u></em><em><u>n</u></em><em><u>,</u></em><em><u> breadth</u></em><em><u>=</u></em><em><u>8</u></em><em><u>i</u></em><em><u>n</u></em>
<em><u>for</u></em><em><u> </u></em><em><u>triangular</u></em><em><u> </u></em><em><u>part:</u></em><em><u>base=</u></em><em><u>8</u></em><em><u>i</u></em><em><u>n</u></em><em><u>,</u></em><em><u> </u></em><em><u>height=</u></em><em><u>3</u></em><em><u>i</u></em><em><u>n</u></em>
<em><u>area of the given fig:</u></em>
<em><u>area of the given fig:area of 2 triangles +area of rectangle </u></em>
<em><u>
</u></em>
<h2>
<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> </u></em><em><u>you</u></em><em><u><</u></em><em><u>3</u></em></h2>
<h3 />
Answer:
20. AB = 42
21. BC = 28
22. AC = 70
23. BC = 20.4
24. FH = 48
25. DE = 10, EF = 10, DF = 20
Step-by-step explanation:
✍️Given:
AB = 2x + 7
BC = 28
AC = 4x,
20. Assuming B is between A and C, thus:
AB + BC = AC (Segment Addition Postulate)
2x + 7 + 28 = 4x (substitution)
Collect like terms
2x + 35 = 4x
35 = 4x - 2x
35 = 2x
Divide both side by 2
17.5 = x
AB = 2x + 7
Plug in the value of x
AB = 2(17.5) + 7 = 42
21. BC = 28 (given)
22. AC = 4x
Plug in the value of x
AC = 4(17.5) = 70
✍️Given:
AC = 35 and AB = 14.6.
Assuming B is between A and C, thus:
23. AB + BC = AC (Segment Addition Postulate)
14.6 + BC = 35 (Substitution)
Subtract 14.6 from each side
BC = 35 - 14.6
BC = 20.4
24. FH = 7x + 6
FG = 4x
GH = 24
FG + GH = FH (Segment Addition Postulate)
(substitution)
Collect like terms


Divide both sides by -3

FH = 7x + 6
Plug in the value of x
FH = 7(6) + 6 = 48
25. DE = 5x, EF = 3x + 4
Given that E bisects DF, therefore,
DE = EF
5x = 3x + 4 (substitution)
Subtract 3x from each side
5x - 3x = 4
2x = 4
Divide both sides by 2
x = 2
DE = 5x
Plug in the value of x
DE = 5(2) = 10
EF = 3x + 4
Plug in the value of x
EF = 3(2) + 4 = 10
DF = DE + EF
DE = 10 + 10 (substitution)
DE = 20
Answer:
40.2
Step-by-step explanation:
The store's sales equate to $6000
Answer:
Table 1
Step-by-step explanation:
In a function, you are not allowed to have two of the same x-values. Table 1 is the only one to show this.
Table 2 has two (-5)s in the x-column, Table 3 has two (-2)s, and Table 4 has two (-4)s.