Value of 1.2^2=1.44
value of 2^3+17-3*4=8+17-12=13
value of 9^2/3^3= 81/27=3
Answer:
t =17 years
Step-by-step explanation:
The formula for interest
A = P(1+ r/n)^ nt
where a is the amount in the account , p is the principal, r is the rate, n is the number of times compounded per year and t is the time in years
Substituting in what we know
690 = 460 ( 1+ .024/365)^ 365t
690/460 = ( 1+ .024/365)^ 365t
1.5 = ( 1+ .024/365)^ 365t
Taking the log of each side
log(1.5) = 365t log( 1+ .024/365))
Dividing each side by( 1+ .024/365)
log(1.5)/ log( 1+ .024/365) = 365t
divide each side by 365
1/365 log(1.5)/ log( 1+ .024/365) =t
t =16.8949
To the nearest year
t =17
With lower case numbers and numerals from 0-9 there are about <u>4,738,381,338,321,616,896 possible passwords.</u>
<u></u>
Add up the number of possible numbers and letters.
There are 26 letters in the alphabet, 0-9 would mean 10 digits. Which is 36.
The length of the password she wants is 12.
36 to the power of 12 = 4738381338321620000
4738381338321620000
Answer:
x=
5
/2
,
−
4
Step-by-step explanation:
Factor and set each factor equal to zero.
First we note symmetry in the expression's coefficients.
We also note that 7*3=21, and 7+3=10.
From the rational roots theorem, we are tempted to try with 3 and 7 as coefficients of the factors.
Try
(7b+3)(3b+7)=21b^2+(49+9)b+21
By switching the sign of 3b+7 to 3b-7, we get the signs right, to check:
(7b+3)(3b-7)=21b^2+(9-49)b-21=21b^2-40b-21 ....right!
So
(7b+3)(3b-7)=21b^2-40b-21
