The complete question is
Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's age is 36. Find <span>the age of Susan and Steven
let
x-----> </span>Susan's age
y----> Steven's age
we know that
y+x=33-----> equation 1
3y-x/2=36----> multiply by 2----> 6y-x=72----> equation 2
adds equation 1 and equation 2
y+x=33
6y-x=72
-------------+
7y=105--------> y=15
x=33-y----> x=33-15----> x=18
the answer is
Susan's age is 18
Steven's age is 15
Answer:
1875.6 in³
Step-by-step explanation:
(⅓×3.14×8²×12) + (⅔×3.14×8³)
1875.626667 in³
First combine like terms and put the expression in standard form. This expression is now in simplest form and cannot be simplified anymore.
3a + 10ab - 7a^2b - 10ab^2 + 12ab - (-4) + (-a^2b) - 5a
-10ab^2 - 8a^2b -2a + 24ab - (-4)
Hope this helps
Answer:
y = 5; x = 1/5
Step-by-step explanation:
xy = 1 -----> x = 1/y
xy^2 = 5 -----> 1/y * y^2 = 5
y^2 / y = 5
y = 5
5x = 1
x = 1/5
Hope this Helps!
Answer:
18 meters if my mental math is right.
