What is the value of x? sin49°=cosx

Alik [6]

Answer:

$d=28.28$

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

The Pythagorean theorem states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

$a^{2} +b^{2} =c^{2}$ a is the height, b is the base, and c is

the hypotenuse.

To obtain the value of the hypotenuse

$c= \sqrt{a^{2} +b^{2} }$

To find the value of the lenght of the diagonal d across the square, we have:

$d=\sqrt{a^{2} +b^{2} }$ Where a = b = 20

Substituting the values

$d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284$

Round the answer to 2 decimal places

$d=28.28$

6 0

3 years ago

Which is the value of 2c2d if c = 0.5 and d = 3? A. 0.15 B. 1.5 C.33 D. 6 E 15

aksik [14]

Answer:

The answer is D (6).

hope this helps!

4 0

2 years ago

Please help! Fill in the missing number.

liq [111]

Answer:

21

Step-by-step explanation:

$\left[\begin{array}{cc}5&9\\-6&9\end{array}\right] +6\left[\begin{array}{cc}-5&2\\7&8\end{array}\right]$

Multiply the second matrix by 6.

$\left[\begin{array}{cc}5&9\\-6&9\end{array}\right] +\left[\begin{array}{cc}-30&12\\42&48\end{array}\right]$

Add the corresponding cells in each matrix.

$\left[\begin{array}{cc}5-30&9+12\\-6+42&9+48\end{array}\right]$

$\left[\begin{array}{cc}-25&21\\36&57\end{array}\right]$

3 0

3 years ago

I WILL MAKE YOU BRAINLIEST

34kurt

Answer:

40

Step-by-step explanation:

32/4=8

8 is 2x 4 so multiply 5x2=10

now multiply 10x4

7 0

3 years ago

Read 2 more answers

Can you please help me find the area? Thank you. :)))

Phoenix [80]

The figure shown in the picture is a rectangular shape that is missing a triangular piece. To determine the area of the figure you have to determine the area of the rectangle and the area of the triangular piece, then you have to subtract the area of the triangle from the area of the rectangle.

The rectangular shape has a width of 12 inches and a length of 20 inches. The area of the rectangle is equal to the multiplication of the width (w) and the length (l), following the formula:

$A=w\cdot l$

For our rectangle w=12 in and l=20 in, the area is:

$\begin{gathered} A_{\text{rectangle}}=12\cdot20 \\ A_{\text{rectangle}}=240in^2 \end{gathered}$

The triangular piece has a height of 6in and its base has a length unknown. Before calculating the area of the triangle, you have to determine the length of the base, which I marked with an "x" in the sketch above.

The length of the rectangle is 20 inches, the triangular piece divides this length into three segments, two of which measure 8 inches and the third one is of unknown length.

You can determine the value of x as follows:

$\begin{gathered} 20=8+8+x \\ 20=16+x \\ 20-16=x \\ 4=x \end{gathered}$

x=4 in → this means that the base of the triangle is 4in long.

The area of the triangle is equal to half the product of the base by the height, following the formula:

$A=\frac{b\cdot h}{2}$

For our triangle, the base is b=4in and the height is h=6in, then the area is:

$\begin{gathered} A_{\text{triangle}}=\frac{4\cdot6}{2} \\ A_{\text{triangle}}=\frac{24}{2} \\ A_{\text{triangle}}=12in^2 \end{gathered}$

Finally, to determine the area of the shape you have to subtract the area of the triangle from the area of the rectangle:

$\begin{gathered} A_{\text{total}}=A_{\text{rectangle}}-A_{\text{triangle}} \\ A_{\text{total}}=240-12 \\ A_{\text{total}}=228in^2 \end{gathered}$

The area of the figure is 228in²

8 0

1 year ago