Answer:
It can hold up to 
of waste
<em></em>
Step-by-step explanation:
Given
-- Diameter
-- height
Required
Determine the amount of waste it can hold
This simply means that we calculate the volume of the cylindrical container.
And this is calculated using:
Where
and
So, we have:
<em>Hence, it can hold up to </em><em> of waste</em>
Step-by-step explanation:
the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).
so,
1.
(9, 7) to (4, -3)
midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)
2.
(-7, -5) to (2, 1)
midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)
3.
now we have the midpoint and need the second point.
(4, 2) over (3, 4) to (x, y)
3 = (4 + x)/2
6 = 4 + x
x = 2
4 = (2 + y)/2
8 = 2 + y
y = 6
4.
(-2, 1) over (-3, 2) to (x, y)
-3 = (-2 + x)/2
-6 = -2 + x
x = -4
2 = (1 + y)/2
4 = 1 + y
y = 3
2
X - 4 when you use the foil method or multiplication
Huh? there can't be 4 zeroes. but if u mean 140,000,000,000; then it's 140 billion.
it u mean 14,000,000,000; then that's 14 billion.
Lets go step by step and factor out each as we go
first lets factor out a 3 since 3 is common in 9 and 3
3(3ab^2 - abc)
now lets factor out a since its common in both
3a(3b^2 - bc)
now lets factor out a b since its common in both
3ab(b - c)
we can't factor anything else out so we are done.
