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oee [108]
3 years ago
10

Kevin is observing the population of the fish he put into a pond. He built a pond and populated it with 500 fish. The population

of the fish doubles every year. Use x to represent the number of years and y to represent the population of the fish. Enter an equation that represents this scenario in the box.
Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0
Given that the number of years should be represented with x, the number of fish in the pond after x years should best be represented with f(x). The equation that would best show the given scenario in the problem above is,
                             f(x) = 500(2^x)
From the given, 500 is used as the initial population of the fish. 
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Question 10: If the product of all the numbers from 1 to 100 is divisible by 2^n, then what is the maximum possible value for n:
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Answer: D

Step-by-step explanation:

100!=2*3*4*...*100

Counting which numbers are divisible by 2:

2,4,6,8,10,12,14,...,96,98,100 : 50 numbers (100/2=50)

Counting which numbers are divisible by 4=2²:

4,8,12,16,20,...96,100: 25 numbers (100/4=25)

Counting which numbers are divisible by 8=2³:

8,16,24,32,40,...,96: 12 numbers (100/8=12.5 ==> 12)

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Counting which numbers are divisible by 64=2⁶:

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4 0
3 years ago
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20 points, please help
Damm [24]

Answer:

The answer to your question is:    83 + 6\sqrt{35}

Step-by-step explanation:

This is a square of a binomial.

                                  (2\sqrt{5} + 3\sqrt{7} )^{2}

1.- Square of the first term

                               ( 2\sqrt{5} )^{2} = 4(5) = 20

2.- Twice the product of the two terms

               (2)(2\sqrt{5} )(3\sqrt{7} ) = 6\sqrt{35}

3.- Square of the second term

                              (3\sqrt{7)})^{2} = 9(7) = 63

4.- Write the solution

                           20 + 6\sqrt{35} + 63

                            83 + 6\sqrt{35}

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