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Svetradugi [14.3K]
4 years ago
8

PLEASE HELP!!!!!!!!!!!!!!!!! Solve. −1/2x + 1/3 > 3/5

Mathematics
1 answer:
Shtirlitz [24]4 years ago
5 0
To solve this inequality, you must first isolate the term that includes the variable, which is -1/2x. This can be done by first subtracting 1/3 from both sides.

Before you can subtract 1/3 from 3/5, however, you must first convert the fractions to have common denominators.
A common denominator for 1/3 and 3/5 is 15. This is the LCM, least common multiple, of 3 and 5, making it the lowest possible common denominator.
Using this common denominator, 1/3 changes to 5/15 and 3/5 changes to 9/15.

Now we can subtract these equivalent fraction for 1/3, which is 5/15, from the fraction equivalent to 3/5, which is 9/15.
9/15 - 5/15 = 4/15
This fraction can't be simplified any further so this step is done.

Now the inequality is -1/2x > 4/15.
The next step is to isolate x by dividing both sides by -1/2.
An important note to remember when doing this step is that whenever dividing by a negative in inequalities, you must flip the inequality symbol.
In this case, that means dividing both sides by -1/2 and changing the greater than sign (>) to a less than sign (<).

-1/2x ÷ -1/2 = x

4/15 ÷ -1/2
When dividing fractions, find the reciprocal of the second fraction then multiply.
The reciprocal of -1/2 is -2/1, or -2 when simplified.
4/15 • -2 = -8/15

This means x < -8/15.
This has x isolated and the inequality simplified as far as possible.
That means this is the answer.

Answer:
x < -8/15

Hope this helps!
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consider the following quadratic function f(x)= -2x^2+12x+32=0 select all the statements that are true for the function
Naddika [18.5K]

Answer:

The answer to your question is

a) 400

b) The function has two real solutions (-2 and 8)

Step-by-step explanation:

Process

1.- Discriminant = b² - 4ac

                         = 12² -4(-2)(32)

                         = 144 + 256

                        = 400

2.- Solutions (using the general formula)

                   x = \frac{- b +/- \sqrt{b^{2}- 4ac}}{2a}

                   x = \frac{- 12 +/- \sqrt{400}}{2(-2)}

                   x = \frac{-12 +/- 20}{2(-2)}

   x₁ = \frac{-12 + 20}{2(-2)} = \frac{-12 + 20}{-4} = \frac{-8}{4} = - 2

   x₂ = \frac{- 12 - 20}{- 4} = \frac{-32}{- 4} = 8

This function has two real solutions (-2, 8)

7 0
4 years ago
4. Ayla purchased two pairs of jeans for $30.50 and a shirt for $20.75. She paid with a one hundred dollar bill
vodomira [7]
She will receive $48.75 back.
5 0
3 years ago
Read 2 more answers
Which has no solution will make brainlist if answer asap
NeX [460]
I think D but I’m not really sure
7 0
4 years ago
I need help please and thank you
Dmitrij [34]
4) split this into two shapes, a rectangle and a triangle...
Rectangle: base(height)
14(7)=98
Triangle: 1/2base(height)
Find the height: 14-7=7
1/2(14)(7)=49
Add them together: 98+49=147
147in^2

5) split this into two shapes, a square and a triangle...
Square: base(height)
20(20)=400
Triangle: 1/2base(height)
1/2(20)(10)=100
Add them together: 400+100=500
500m^2

6) split this into 2 shapes, a rectangle and a triangle...
Rectangle: base(height)
6(5)=30
Triangle: 1/2base(height)
1/2(6)(3)=9
Add them together: 30+9=39
39yd^2

7) I can't see the number behind the m. Please tell me what it is and then I'll help you!

8) split this into 2 shapes, a rectangle and a triangle...
Rectangle: base(height)
5(2)=10
Triangle: 1/2base(height)
1/2(5)(3)=7.5
Add them together: 10+7.5=17.5
17.5ft^2

9) split this into 2 shapes, a rectangle and a triangle...
Rectangle: base(height)
13.5(18)=243
Triangle: 1/2base(height)
1/2(13.5)(9)=60.75
Add them together: 243+60.75=303.75
303.75cm^2


I hope this helps:)
BEST WISHES!
7 0
3 years ago
PLEASE HELP!!!
Oksanka [162]

Answer:

PLEASE HELP!!!

1. Under what conditions must we assume a Student t distribution for the sampling distribution of sample means when testing a claim about a population mean?

2. Give one difference between the Student t distribution and the normal distribution.

3. Which TI-84 calculator command or StatCrunch dialog box is used to find the P-value given a t test statistic?

Step-by-step explanation:

PLEASE HELP!!!

1. Under what conditions must we assume a Student t distribution for the sampling distribution of sample means when testing a claim about a population mean?

2. Give one difference between the Student t distribution and the normal distribution.

3. Which TI-84 calculator command or StatCrunch dialog box is used to find the P-value given a t test statistic?

4 0
3 years ago
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