</span>→ Rewrite as: (7x²− 2x + 9) + 1(3x²+ 15x − 4) ___________________________________________ Considering the following portion of the expression: ___________________________________________ " 1(3x²+ 15x − 4) " ; ___________________________________________ Note the "distributive property of multiplication" : ___________________________________________ a(b + c) = ab + ac ;
a(b − c) = ab + ac ; ___________________________________________ Likewise:
a(b + c − d) = ab + ac − ad ; ___________________________________________ So; 1(3x²+ 15x − 4) = (1*3x²) + (1*15x) − (1*4) ;
= 3x² + 15x − 4
Bring down the: "(7x²− 2x + 9)" ; and rewrite the expression: ___________________________________________________
7x² − 2x + 9 + 3x² + 15x − 4 ;
Combine the "like terms" :
+7x² + 3x² = + 10x² ;
- 2x + 15x = + 13x ;
+ 9 − 4 = + 5 ; ____________________________________________________ and rewrite the expression: ____________________________________________________ which is: " 10x² + 13x + 5 " . ____________________________________________________
