Answer:
a. 8.4 ft³
b. 4.44 ft × 2.44 ft × 0.78 ft
Step-by-step explanation:
a. <em>Maximum volume
</em>
We are creating a box with dimensions
l = 6 – 2x
w = 4 – 2x
h = x
V = lwh = x(6 – 2x)(4 – 2x)
We must determine the value of x that makes V a maximum.
One way is to plot the function V = x(6 – 2x)(4 – 2x).
The maximum appears to be at about (0.78, 8.4).
Thus, the maximum volume is 8.4 ft³.
b.<em> Dimensions
</em>
l = 6 – 2 × 0.78 = 6 – 1.56 = 4.44 ft
w = 4 – 2 × 0.78 = 4 – 1.56 = 2.44 ft
h = 0.78 ft
The box with maximum volume has dimensions 4.44 ft × 2.44 ft × 0.78 ft.
I find it easier just to graph this sort of question rather than multiply it all out.
x = 3.5
_____
(x^2 +2x +1) -(x^2 -6x +9) = 20
.. 8x -8 = 20
.. x = 28/8 = 3.5
Answer:
b^2+2*a*b+a^2
Step-by-step explanation:
Answer:
about 0.0143 microfarads
Step-by-step explanation:
The effective capacitance of capacitors in series is the reciprocal of the sum of their reciprocals:
1/(1/0.02 +1/0.05) = 1/(50+20) = 1/70 ≈ 0.0143 . . . microfarads
The greatest whole number is 300,000