<h2>Answer:</h2>
Option: D is the correct answer.
D. x < 397.9 and x > 402.1
<h2>Step-by-step explanation:</h2>
It is given that:
Each bag is advertised as weighing 400 grams.
Also, a bag must weigh within 2.1 grams in order to be accepted.
Hence, for the bag being accepted the weight must be no less than 2.1 gram from 400 gram and should be no more than 2.1 gram from 400 grams.
i.e. the weight of the bag must be such that:
400-2.1≤ x ≤ 400+2.1
i.e.
397.9 ≤ x ≤ 402.1
Hence, if the weight of the bag is less than 397.9 grams or is more than 402.1 grams then the bag will be rejected.
i.e. The range for the bag being rejected is: x<397.9 grams and x>402.1 grams.
Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
.666 gallons, you multiply 8/9 by 3/4
and thats how you do it.
Answer:
X =8
EF=12
FG=17
Step-by-step explanation:
