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snow_tiger [21]
3 years ago
10

Pls help LOL I need helo

Mathematics
1 answer:
Andrews [41]3 years ago
5 0
500$ if that’s an answer
You might be interested in
Compare 6.23x10^14 and 8.912x10^12
Tju [1.3M]

Answer:

hello : 6.23x10^14 >  8.912x10^12^12

Step-by-step explanation:

let : A= 6.23x10^14 and  B =  8.912x10^12

A= (6.23x10^2) x10^12  ... because : 10^14 = 10^2x10^12

A = 623 x 10^12

623 > 8.912

so : A > B

3 0
4 years ago
Find modulus and principle argument of compiles numbers Z=5/2(cos300+isin300)
Paul [167]

z = \frac{5}{2}(\cos(300) + i\sin(300)) = \frac{5}{2}(\frac{1}{2} - i\frac{\sqrt{3}}{2})\\|z| = \sqrt{(\frac{5}{4})^2 + (\frac{5\sqrt{3}}{4})^2} = \sqrt{\frac{25}{16} + \frac{75}{16}} = \sqrt{\frac{100}{16}} = \frac{10}{4} = \frac{5}{2}

7 0
3 years ago
I really suck at math plz help me
inysia [295]
You would have to have common demoniators to add.
8/10 can be turn into 80/100 by multiplying the denominator and nominator by ten
75/100+80/100, you add the nominators ONLY, dont change the denominator.
75+80=155

so your answer would be 155/100
4 0
4 years ago
Read 2 more answers
WILL GIVE BRAINLIEST! <br>What is the answer for question (iv)? <br>please help! ​
Leviafan [203]

Step-by-step explanation:

\triangle ABC \sim \triangle ADE... (given) \\\\\therefore \frac {AC}{AE} = \frac {BC}{DE}.. (csst) \\\\\therefore \frac {5}{5+2x} = \frac {x+3}{4x+1}\\ \\ \therefore \: 5(4x + 1) = (5 + 2x)(x + 3) \\ \therefore \:20x + 5 = 5x + 15 + 2 {x}^{2}  + 6x \\ \therefore \:20x + 5 =2 {x}^{2} +  11x + 15 \\ \therefore \:2 {x}^{2} +  11x + 15 -2 0x  - 5 = 0\\  \therefore \:2 {x}^{2}  - 9x + 10 = 0\\ \therefore \:2 {x}^{2}  - 5x   -  4x+ 10 = 0\\ \therefore \:x(2x - 5) - 2(2x - 5) = 0 \\ \therefore \:(2x - 5)(x - 2) = 0 \\ 2x - 5 = 0  \:  \: or \:  \: x - 2 = 0 \\ x =  \frac{5}{2} \:  \:  or \:  \: x = 2 \\ x = 2.5 \:  \: or \: x = 2 \\ x = 2.5 \: is \: largest \\  \\  \frac{A(\triangle ABC)}{ A(\triangle ADE)} =  \frac{AC ^{2} } {AE^{2} } \\  \\ \frac{A(\triangle ABC)}{ A(\triangle ADE)} =  \frac{5 ^{2} } {(5 + 2x)^{2} } \\  =  \frac{25}{(5 + 2 \times 2.5)^{2} }  \\  =  \frac{25}{ {10}^{2} }  \\  =  \frac{25}{100}  \\  \\  \frac{A(\triangle ABC)}{ A(\triangle ADE)} =  \frac{1}{4}  \\

5 0
4 years ago
Someone please help me
Mashcka [7]
To solve this, we would need to know some trigonometry. 
To solve this, the equation would be this:
tan 37= x/3.
If we solve this, line segment DE would be approximately 2.26.
Hope this helps.
4 0
3 years ago
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