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Reil [10]
3 years ago
6

4b. why would the vena cava be classified as a vein? all veins carry blood back to the heart, except for the pulmonary vein. the

vena cava empty into the right side of the heart, so they technically bring blood to the
Biology
1 answer:
padilas [110]3 years ago
3 0
The answer is that <span>all veins carry blood back to the heart, except for the pulmonary vein. the vena cava empty into the right side of the heart, so they technically bring blood to the </span>main atrium.
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The type of inheritance that involves the partial expression of two different
liraira [26]

Answer:

D. Codominance

Explanation:

Codominance is when both alleles are expressed with the resulting phenotype being the intermediate of the two. For example, red and white phenotypes results to a pink one.

3 0
2 years ago
Which statement below is correct? a) the arms are medial to the heart b) the heart is medial to the arms. c) the wrist is medial
Vitek1552 [10]

Answer:

The heart is medial to the arms

8 0
3 years ago
What caused the Minnesota frogs to have malformed limbs?​
snow_lady [41]

Answer:

A parasites is known to cause malformations, but only when it attacks tadpoles at a certain point in their development. Predators can cause missing or shortened limbs, as a partially eaten tadpoles regenerate lost tissues.

3 0
3 years ago
An event lasts 4 hours and 20 minutes. How long did the event last in seconds?
daser333 [38]

The event last in 15,600 seconds.

Answer: Option B

<u>Explanation:</u>

We know that there is 60 seconds in one minute i.e., 1 minute = 60 seconds

There is 60 minutes in one hour. i.e., 60 minutes = 1 hour.

Given : An event lasts 4 hours and 20 minutes

4 hours contains 240 minutes,

               4 \times 60=240 \text { minutes }

When the above expressed in seconds,

              240 \times 60=14400 \text { seconds } ------>eq. 1

When 20 minutes expressed in seconds,

              20 \times 60=1200 \text { seconds }------->eq. 2

Adding both eq. 1 and 2, we get

          4 hours and 20 minutes = 14400 + 1200 = 15600 seconds

7 0
3 years ago
g a true breeding pea plant with round and green seeds was crossed to a true-breeding pea plant with wrinkled and yellow seeds.
Sveta_85 [38]

Answer:

The probability of producing a round and green plant from this cross is 3/16

Explanation:

This question involves two distinct genes coding for seed shape and seed colour. In the seed shape gene, allele for round seeds (R) is dominant over allele for wrinked seeds (r), while in the seed colour gene, allele for yellow seed (Y) is dominant over allele for green seeds (y).

A truebreeding plant means that the plant possesses homozygous genotype. Hence, a truebreeding pea plant with round and green seeds will have genotype: RRyy while true-breeding pea plant with wrinkled and yellow seeds will have genotype: rrYY. These two parents will produce F1 offsprings with genotype: RrYy (heterozygous).

When the F1 offsprings are self-crossed (RrYy × RrYy), the following allelic combinations of gametes will be produced by each F1 parent: RY, Ry, rY, ry

Using these gametes in a punnet square (see attached image), 16 possible F2 offsprings with a phenotypic ratio 9:3:3:1 will be produced

9- Round yellow offsprings (R_Y_)

3- Round green offsprings (R_yy)

3- Wrinkled yellow offsprings (rrY_)

1- Wrinkled green offsprings (rryy)

8 0
3 years ago
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