All categories

3 years ago

Demonstrate that plants use photosynthesis to grow throughout their lives

1 answer:

3 0

By definition, photosynthesis is the process made by green plants, algae and some other forms of bacteria to make their own food by converting carbon dioxide and water into glucose.

So how important is photosynthesis to plants? It is as important as how humans need food in order to survive. Plants also need food and energy to survive and grow.

Not only food is the important matter to be addressed when it comes to photosynthesis. It is also important for plants' cellular respiration. These processes are constantly made by plants throughout their entire life.

You might be interested in

Which represents potential energy?

uysha [10]

C) is the correct answer.

8 0

4 years ago

Read 2 more answers

Now assume that the boat is subject to a drag force fd due to water resistance. is the component of the total momentum of the sy

DochEvi [55]

Based on the given details with this question, I can say that the direction of motion is not conserved. This is because the boat is subjected to an external force because of water resistance. So, the answer for this question would be NO.

4 0

3 years ago

Read 2 more answers

Do the math for 30%÷75

Dafna1 [17]

" 30% " means " 0.30 "

30% ÷ 75 means (0.30 / 75) = <em>0.004</em>

3 0

3 years ago

A Porsche sports car can accelerate at 8.8 m/s^2. Determine its acceleration in km/h^2.

finlep [7]

Answer:

The acceleration expressed in the new units is $114.048 Km/h^{2}$

Explanation:

To convert from $m/s^{2}$ to $Km/h^{2}$ it is necessary to remember that there are 1000 meters in 1 kilometer and 3600 seconds in 1 hour:

Then by means of a rule of three it is get:

$8.8\frac{m}{s^{2}}.(\frac{1Km}{1000m}).(\frac{3600s}{1h})^{2}$

$8.8\frac{m}{s^{2}}.(\frac{1Km}{1000m}).(\frac{12960000s^{2}}{1h^{2}})$

Hence, the units of meters and seconds will cancel. Notice the importance of square the ratio 3600s/1h, so that way they can match with the other units:

$114.048 Km/h^2$

So the acceleration expressed in the new units is $114.048 Km/h^2$ .

6 0

4 years ago

Calculate the ratio of the drag force on a jet flying at 950 km/h at an altitude of 10 km to the drag force on a prop-driven tra

Black_prince [1.1K]

Answer:

$\frac{F_1}{F_2}=3.55$

Explanation:

F = Force

C = Drag coefficient equal for both aircrafts

ρ = Density of air

A = Surface area equal for both aircrafts

v = Velocity

$v_2=\frac{2}{5}v_1$

$F_1=\frac{1}{2}\rho_1 CAv_1^2$

$F_2=\frac{1}{2}\rho_2 CAv_2^2\\\Rightarrow F_2=\frac{1}{2}\rho_2 CA\left(\frac{2}{5}v_1\right)^2$

Dividing the above two equations we get

$\frac{F_1}{F_2}=\frac{\frac{1}{2}\rho_1 CAv_1^2}{\frac{1}{2}\rho_2 CA\left(\frac{2}{5}v_1\right)^2}\\\Rightarrow \frac{F_1}{F_2}=\frac{\rho_1}{\rho_2\frac{4}{25}}\\\Rightarrow \frac{F_1}{F_2}=\frac{0.38}{0.67\frac{4}{25}}\\\Rightarrow \frac{F_1}{F_2}=3.55$

The ratio of the drag forces is $\mathbf{\frac{F_1}{F_2}}=\mathbf{3.55}$

5 0

3 years ago