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2 years ago

Explain the conservation of energy in terms of the energy transformation(s) that occur when you strike (light) a match.

Physics

1 answer:

Amiraneli [1.4K]2 years ago

8 0

Answer:

The conservation of energy of energy states that energy can neither be created nor destroyed but can be transferred from one form to other. It also states that energy of bodies remain constant in a closed system.

While striking (light) a match, the mechanical energy is utilized is transformed to thermal energy, this thermal energy then releases the chemical energy stored in match. The chemical energy at the ends transform to thermal energy which is visible as as light.

So, in this the energy transformation that occurs remain constant.

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Light waves are:<br> O Transverse waves<br> O Longitudinal Waves

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Answer:

They are Transverse Waves.

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2 years ago

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An injured monkey sits perched on a tree branch 3.0 m above the ground, while a wildlife veterinarian is kneeling down in the bu

Irina18 [472]

here in the given situation if monkey starts free fall at the same instant when veterinarian shoots towards it then we know that vertical component of motion of monkey and the dart will be same as under gravity

so here the dart will always hit the monkey because they both moves under same acceleration

so here for the angle we can use

$tan\theta = \frac{H}{L}$

now we have

H = 3 m

L = 87.5 m

now we will have

$tan\theta = \frac{3}{87.5}$

$tan\theta = 0.034$

$\theta = 1.96 degree$

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2 years ago

On the earth, when an astronaut throws a 0.250 kg stone vertically upward, it returns to his hand a time T later. On planet X he

Igoryamba

Answer: $\frac{g}{2}$

Explanation:

Given

mass of stone $\left ( m\right )$ =0.250 kg

Let initial velocity with which it is thrown upward is u

therefore after time t it's velocity is zero at highest point

t= $\frac{u}{g}$

where g= gravity at earth

therefore $T=2\times \frac{u}{g}$ -------1

Now same thing is done in Planet X where gravity is g'

therefore time taken by stone to reach surface is

$T'=T=2\times \frac{u}{g'}$ -------2

Divide 1 & 2

$\frac{T}{T'}$ = $\frac{g'}{g}$

$\frac{1}{2}$ = $\frac{g'}{g}$

g'= $\frac{g}{2}$

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2 years ago

Important!

9966 [12]

I think that it’s the first one

4 0

3 years ago

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Two diodes are in series. The first diode has a voltage of 0.75 V and the second has a voltage of 0.8 V. If the current through

tensa zangetsu [6.8K]

The current in the second diode is 400mA

Data;

First Voltage = 0.75V
Second Voltage = 0.8V
First Current (I) = 400mA
Second Current(I) = ?

<h3>Current In a Series</h3>

The current in the first diode is equal to 400mA. In a series circuit, the current passing the diodes are equal. This implies that the current in the series are equal.

Diodes connected in series will be the equal.

$I_1 = I_2$

Since I1 is 400mA, I2 will be equal to 400mA

$I_1 = I_2\\I_1 = 400mA\\I_2 = 400mA$

The current in the second diode is 400mA

Learn more on current in a diode here;

brainly.com/question/1455378

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2 years ago