Answer:not 100 % sure but I can write a slope intercept form equation, but not an inequality. I would need a picture of the graph to write an inequality.

First find slope: (y2 - y1)/(x2 - x1) Slope is 3

Choose a point then use point slope form y - y1 = m(x - x1) It is y - 1 = 3(x - 1)

Now simplify:

y - 1 = 3(x - 1)

y - 1 = 3x - 3

y = 3x - 2

Step-by-step explanation:

8 0

2 years ago

D/6=3, d=18. True or False

melamori03 [73]

True because 6 multiplied by 3 is 18. Therefore, when you divide 18 by 6 the anwser will be 3.

6 0

2 years ago

Read 2 more answers

What’s the correct answer <br> I need a correct answer ASAP!!!!!

Illusion [34]

Answer:

the first answer

3 1/3 that's the correct answer

5 0

2 years ago

How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$

5 0

3 years ago