Prove that the absolute value of the sum is less than the sum of the absolute values
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6f-1 and 2f+ 4f +2-3 are equal. 2f +4f+2-3 is 17 at f=3 because
(2•3)+(4•3)+(2-3) =
(6+12)+(-1) =
(18)+(-1)=
17
Plug in what f equals for f in the equation and evaluate
I hope this helps.
(2•3)+(4•3)+(2-3) =
(6+12)+(-1) =
(18)+(-1)=
17
Plug in what f equals for f in the equation and evaluate
I hope this helps.