Prove that the absolute value of the sum is less than the sum of the absolute values

Natasha had a pizza party with two of her friends.to celebrate reading 50 books each. Everyone got their own pizza. Natasha ate

Alisiya [41]

Answer:

ffffffffff

Step-by-step explanation:

6 0

3 years ago

Is there more than one way to get 2/3/4/5 to the simplest form

seropon [69]

Multiply 2 and 3 also multiply 4 and 5 and then divide the products together like so 2x3 divided by 4x5 so 6 divided by 20

4 0

3 years ago

What is the answer of 2+4 5+1 1+1 0+0

Dahasolnce [82]

Answer:

14

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The low temperature was -1.8 C yesterday and -2.1 C today. Use the symbols < or > to show the relationship between the tem

Free_Kalibri [48]

I don’t really know what the question is looking for but -1.8 C > -2.1C

5 0

3 years ago

Read 2 more answers

Help!! algebra two!! c-h :)

kotegsom [21]

Answer:

c. (2x + 3y)² = (2x)² + 2(2x)(3y) + (3y)²

d. (w - 1)(1 + w + w²) =  w³ - 1

e. a² - 16 = (a + 4)(a - 4)

f. (2x + 5y)(2x - 5y) = 4x² - 25y²

g. (2²¹ - 1)(2²¹ + 1) = 2⁴² - 1

h. [(x - y) - 3][(x - y) + 3] = (x - y)² - 9

Step-by-step explanation:

c. Although this expression, when squared, is really 4x² + 12xy + 9y², they just splitted it up into several more terms. In this last blank should be a 9y², but instead, they took the square root of the term, which is 3y, and set the square outside of the parentheses.

*I bet that was what made it confusing, but have no fear. The mathematics tutor is here.

d. This is similar to the Quadratic Equation [y = Ax² + Bx + C] where you can, what I like to call... FOIL it, however, you have an extended amount of terms. Although you still have to FOIL it, it is just a unique procedure. This time, you have to one-by-one, take each term in the first set of parentheses [-1 and w] and multiply them by the second all three terms in the second set of parentheses.

e. This is a piece of cake because we know BOTH square roots of 16 and we are multiplying what are called conjugates.

f. Again, we are multiplying conjugates, so we just multiply the first and last two terms in each set of parentheses.

g. Again, we are multiplying conjugates EXCEPT now, we have exponents in each set of parentheses. Whenever you multiply terms, you add the exponents and your base remains the same, which is what you see in the above answer.

h. For the final exercise, we are multiplying conjugates again, and we obviously can see what fills that blank because there are TWO IDENTICAL EXPRESSIONS that are being multiplied, which in this case are being "squared", and that expression is x - y. It appears twice, so that is a giveaway.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**Conjugates are IDENTICAL expressions with OPPOSITE operation symbols. Whenever you multiply conjugates, just add the first and last two terms in both sets of parentheses because when you FOIL, the midst term will ALWAYS result in zero.

8 0

4 years ago