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Tanzania [10]
3 years ago
10

Help!! algebra two!! c-h :)

Mathematics
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

c. (2x + 3y)² = (2x)² + 2(2x)(3y) + (<u>3y</u>)²

d. (w - 1)(1 + w + w²) = <u> </u><u>w³</u> - 1

e. a² - 16 = (a + <u>4</u>)(a - <u>4</u>)

f. (2x + 5y)(2x - 5y) = <u>4x²</u> - <u>25y²</u>

g. (2²¹ - 1)(2²¹ + 1) = <u>2⁴²</u> - 1

h. [(x - y) - 3][(x - y) + 3] = (<u>x - y</u>)² - 9

Step-by-step explanation:

c. Although this expression, when squared, is really <em>4x</em><em>²</em><em> </em><em>+</em><em> </em><em>12xy</em><em> </em><em>+</em><em> </em><em>9y</em><em>²,</em><em> </em>they just splitted it up into several more terms. In this last blank should be a 9y², but instead, they took the square root of the term, which is <em>3y,</em><em> </em>and set the square outside of the parentheses.

*I bet that was what made it confusing, but have no fear. The mathematics tutor is here.

d. This is similar to the Quadratic Equation [<em>y</em><em> </em><em>=</em><em> </em><em>Ax</em><em>²</em><em> </em><em>+</em><em> </em><em>Bx</em><em> </em><em>+</em><em> </em><em>C</em>] where you can, what I like to call... FOIL it, however, you have an extended amount of terms. Although you still have to FOIL it, it is just a unique procedure. This time, you have to one-by-one, take each term in the first set of parentheses [-1 and w] and multiply them by the second all three terms in the second set of parentheses.

e. This is a piece of cake because we know BOTH square roots of 16 and we are multiplying what are called conjugates.

f. Again, we are multiplying conjugates, so we just multiply the first and last two terms in each set of parentheses.

g. Again, we are multiplying conjugates EXCEPT now, we have exponents in each set of parentheses. Whenever you multiply terms, you add the exponents and your base remains the same, which is what you see in the above answer.

h. For the final exercise, we are multiplying conjugates again, and we obviously can see what fills that blank because there are TWO IDENTICAL EXPRESSIONS that are being multiplied, which in this case are being "squared", and that expression is <em>x</em><em> </em><em>-</em><em> </em><em>y</em><em>.</em><em> </em>It appears twice, so that is a giveaway.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**Conjugates are IDENTICAL expressions with OPPOSITE operation symbols. Whenever you multiply conjugates, just add the first and last two terms in both sets of parentheses because when you FOIL, the midst term will ALWAYS result in zero.

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likoan [24]

Answer:

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5 0
3 years ago
la edad de josé y beatriz están en la relacion de 5 a4 . si dentro de 3 años la suma de ambas edades seran 60 años , ¿ cual es l
miss Akunina [59]

Answer:

La edad actual de Beatriz es de:

30 años

Step-by-step explanation:

Planteamiento:

5e = 4b

(e+3) + (b+3) = 60

e = edad actual de José

b = edad actual de Beatriz

Desarrollo:

de la segunda ecuación del planteamiento:

e + b + 6 = 60

e + b = 60 - 6

e + b = 54

e = 54 - b

sustituyendo este último valor en la primer ecuación del planteamiento:

5(54-b) = 4b

5*54 + 5*-b = 4b

270 - 5b = 4b

270 = 4b + 5b

270 = 9b

b = 270/9

b = 30

e = 54 - b

e = 54 - 30

e = 24

Comprobación:

5e = 4b

5*24 = 4*30 = 120

3 0
3 years ago
There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am
Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

n = 479, \pi = \frac{130}{479} = 0.2714

Hence the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
Pls help I will mark brailiest​
Elena L [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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