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RUDIKE [14]
3 years ago
9

Which statement is true about the end behavior of the graphed function?

Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0

Answer:

A.

As the x-values go to positive infinity, the function's values go to negative infinity.

Step-by-step explanation:

Tems11 [23]3 years ago
6 0

Answer:

(SEE EXPLANATION FIRST)

Answer D is TRUE because on the graph if you were to keep going left even after the picture of the graph ends, the graph will still keep going up infinite

Step-by-step explanation:

If this is the graph you can read the answer

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The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normal
adell [148]

Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma}

a) For x < 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

From normal distribution table,  P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%

b) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337  

c) For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table,  P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) =  0.2033- 0.0188 = 0.1845  

e) For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table,  P(x < 5) = P(z < -0.83) = 0.2033

8 0
3 years ago
What is the quotient
mario62 [17]

Answer:

The quotient is 3x - 11 + 60/(x + 5) ⇒ 2nd answer

Step-by-step explanation:

* We will use the long division to solve the problem

- The dividend is 3x² + 4x + 5

- The divisor is x + 5

- The quotient is the answer of the division

- If the divisor not a factor of a dividend, the quotient has

  a remainder

* Lets solve the problem

- At first divide the first term in the dividend by the first term in

 the divisor

∵ 3x² ÷ x = 3x

- Multiply the divisor by 3x

∴ 3x (x + 5) = 3x² + 15x

-Subtract this expression from the dividend

∴ 3x² + 4x + 5 - (3x² + 15x) = 3x² + 4x + 5 - 3x² - 15x = -11x + 5

- Divide the first term -11x in the new dividend by the first

 term x in the divisor

∴ -11x ÷ x = -11

- Multiply the divisor by -11

∴ -11(x + 5) = -11x - 55

-Subtract this expression from the new dividend

∴ -11x + 5 - (-11x - 55) = -11x + 5 + 11x + 55 = 60

∴ The quotient is 3x - 11 with remainder = 60

* The quotient is 3x - 11 + 60/(x + 5)

5 0
3 years ago
Hi, I need the area to this problem i need the answer and to show my work no hackers please <br>​
Harrizon [31]
28 yards is the answer
4 0
2 years ago
Pls help pls pls ): precalc
Lena [83]
<h3>Answer: Choice A</h3>

\log_p N = b is not the same as b^p = N

The base of the log is p, while the base of the exponential is b. The two don't match. If it said \log_p N = b \text{ is the same as } p^b = N then it would be a valid statement since the bases are both p.

-----------------

Extra info:

Choice B is a valid statement because Ln is a natural log with base 'e'

Choice C is valid as any square root is really something to the 1/2 power

Choice D is valid for similar reasons mentioned earlier

5 0
3 years ago
Read 2 more answers
Please help me i am really bad at math
nlexa [21]

Answer:

the expression is -5 + 2. the sum is -3.

Step-by-step explanation:

5 0
3 years ago
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