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vladimir2022 [97]
3 years ago
9

O preço do diesel sofreu três alterações ao longo do último trimestre de 2017. A primeira alteração foi em outubro, cujo aumento

foi de 10% no preço inicial do produto. Em novembro, houve um novo aumento, agora de 20%. Em dezembro, em função das datas festivas, 12% de aumento sobre o preço final de novembro. A variação do preço da diesel acumulada no último trimestre do ano em relação ao seu preço inicial foi de:
Mathematics
1 answer:
EleoNora [17]3 years ago
5 0

Answer:

47.84%

Step-by-step explanation:

The easiest method to solve this exercise is to assume that the starting diesel price is 100 reais.

Now we will calculate each increase with our assumption:

1. Initial price plus 10% increase, therefore:

100 + 100 * 0.1 = 110 reais

2. Additional 20% increase in relation to 110 reais:

110 + 110 * 0.2 = 132 reais

3. Additional 12% increase in relation to 132 reais:

132 + 132 * 0.12 = 147.84 reais.

What it means is that the price would be 147.84 reais.

Since our assumption is 100, we can know that there was an increase of almost 47.84% in relation to the initial price that we assumed at the beginning.

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325.15

Step-by-step explanation:

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a monument casts a 40-foot shadow. Adam is 6 feet tall and casts a 5-foot shadow. How tall is the monument
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In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population
Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

y=a(1+r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>t</em> = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of <em>r</em> as follows:

y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145

Now, compute the time it will take the population to grow to 800 insects as follows:

800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17

Thus, the time it will take the population to grow to 800 insects is 17 days.

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3 years ago
How to find horizontal and vertical asymptotes from equations?
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