(y x .12) x .3 = the total cost
Answer:
2002 pounds
Explanation:
To know the weight of the plane, we need to find an equation that relates the amount of fuel to the weight.
This equation can be founded using the following

Where m is the slope, x1 is the number of gallons and y1 is the respective weight. So, replacing m = 6.0, x1 = 51 gallons and y1 = 2206 pounds, we get:

Now, we can solve for y

Then, we can calculate the weight of an airplane with 17 gallons of fuel replacing x = 17 on the equation above
y = 6x + 1900
y = 6(17) + 1900
y = 102 + 1900
y = 2002
Therefore, the answer is 2002 pounds
9514 1404 393
Answer:
3) x = 9
4) x = 3
Step-by-step explanation:
3) The two short segments are indicated as having a sum equal to the long segment.
(x +2) +(-5 +x) = 15
2x = 18 . . . . . . . . . . . . add 3
x = 9 . . . . . . . . . divide by 2
(This makes the segments be 9+2 = 11 and -5+9 = 4, which total 15.)
__
4) Same deal.
3x +3 = 4x
3 = x . . . . . . . . subtract 3x
(This makes the segments be 3(3) = 9 and 4(3) = 12, where 9+3=12.)
It would b C because there are 6 sides and out of the 6, you want one number, which is 4, so that’s why it would be C
Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.
Let x be the number of $2 increases in price, then the revenue from renting cars is given by

.
Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by

Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
</span><span>

For maximum profit, the differentiation of the profit function equals zero.
i.e.
</span><span>

The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.
Therefore, the </span><span>rental charge will maximize profit is $64.</span>