I = P x R x T
I = 6000 x .04 x 2
I = $480
He will be paid $480 interest in the first two years
Answer:
17866676666629.933594
Step-by-step explanation:
because oBaMa
Answer:
3+12i
Step-by-step explanation:
The difference of 5+3i and 2 + 1999 can be calculated as follows
= 5+3i - 2+9i
Collect the like terms
= 5-2+3i+9i
= 3+12i
Hence the difference of 5+3i and 2+9i is 3+12i
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
Answer:
2x
Step-by-step explanation:
we can use the Pythagorean Theorem to find the missing side (a):
a² + (2x)² = (8x)²
a² + 4x² = 64x²
a² = 60x²
a = √60x²
a = 
· · 
This can be simplified to be 2x
