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4 years ago

13

Can a quadratic equation considered a quadratic function without a constant term

2 answers:

MArishka [77]4 years ago

6 0

Yes, its quadratic. constant may be zero.

Leviafan [203]4 years ago

3 0

Yes and zero will be the constant

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Determine whether the table of values below represents a linear function. If it represents a linear function, write the function

Rzqust [24]

Answer:

The equation of a linear function is:

$y = 2x+4$

Step-by-step explanation:

Given the table

x y

-10 -16

-3 -2

1 6

2 8

Determining the slope between the points (-10, -16), (-3, -2)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-10,\:-16\right),\:\left(x_2,\:y_2\right)=\left(-3,\:-2\right)$

$m=\frac{-2-\left(-16\right)}{-3-\left(-10\right)}$

$m=2$

Determining the slope between the points (-3, -2), (1, 6)

$m=\frac{6-\left(-2\right)}{1-\left(-3\right)}$

$m=2$

Determining the slope between the points (1, 6),(2, 8)

$m=\frac{8-6}{2-1}$

$m = 2$

As the slope between the points is the same. Thus, the table represents the linear function.

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 2 and any point let say (1, 6)

$y - 6 = 2(x-1)$

$y-6 = 2x-2$

$y = 2x-2+6$

$y = 2x+4$

Therefore, the equation of a linear function is:

$y = 2x+4$

5 0

3 years ago

Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.

Irina18 [472]

Answer:

<u>TO FIND :-</u>

Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$
$\tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}$

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

$=> \sin 16 = \frac{7}{x}$

$=> \frac{7}{x} = 0.27563......$

$=> x = \frac{7}{0.27563....} = 25.39568.....$ ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

$=> \sin 29 = \frac{6}{x}$

$=> \frac{6}{x} = 0.48480......$

$=> x = \frac{6}{0.48480....} = 12.37599.....$ ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

$=> \sin 30 = \frac{x}{11}$

$=> \frac{x}{11} = 0.5$

$=> x = 0.5 \times 11 = 5.5$

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

$=> \cos 43 = \frac{x}{12}$

$=> \frac{x}{12} = 0.73135......$

$=> x = 12 \times 0.73135.... = 8.77624....$ ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

$=> \cos 55 = \frac{x}{6}$

$=> \frac{x}{6} = 0.57357......$

$=> x = 6 \times 0.57357.... = 3.44145....$ ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

$=> \cos 73 = \frac{8}{x}$

$=> \frac{8}{x} = 0.29237......$

$=> x = \frac{8}{0.29237.....} = 27.36242.....$ ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

$=> \tan 69 = \frac{12}{x}$

$=> \frac{12}{x} = 2.60508......$

$=> x = \frac{12}{2.60508....} = 4.60636....$ ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

$=> \tan 20 = \frac{11}{x}$

$=> \frac{11}{x} = 0.36397......$

$=> x = \frac{11}{0.36397....} =30.22225....$ ≈ 30.2

5 0

3 years ago

The length of a rectangle is six times it's width. If the area is 216 inches squared, find its perimeter

Lana71 [14]

I had a problem like this but it was different but what i divided was 216 divided by 12 and got 18 and 216 divided by 6 and got 36

8 0

3 years ago

Read 2 more answers

Can anyone answer this?

defon

Answer:

Ayo its Jose is the only one who was trying to get me to do the thank you usa for the support of the joy luck club the story is about a mother that lost every thing in China and whent to America to start a new life but she make her daughter do something that she don't want to be ninja in and she is not sending her

6 0

2 years ago

It is estimated that the population of the world is increasing at an average rate of 1.09%. The population was about 7,632,819,3

morpeh [17]

Answer:

The equation that represents the population after T years is

$P_{t} = 7,632,819,325 [1 +\frac{1.09}{100} ]^{T}$

Step-by-step explanation:

Population in the year 2018 ( P )= 7,632,819,325

Rate of increase R = 1.09 %

The population after T years is given by the formula

$P_{t} = P [1 +\frac{R}{100} ]^{T}$ -------- (1)

Where P = population in 2018

R = rate of increase

T = time period

Put the values of P & R in above equation we get

$P_{t} = 7,632,819,325 [1 +\frac{1.09}{100} ]^{T}$

This is the equation that represents the population after T years.

6 0

3 years ago