Answer: May 7th i believe
Step-by-step explanation: If they both pick up on may 4th and then they pick up every 3-4 days it would be 7-8 but 3 to 4 it is 3 and a half so the answer would be May 7th. Hope this helps...
The least common multiple of 5 and 8 is 40. This is because when you go by multiples of 5 and 8 the multiple that is the “smallest number” (LCM) of both numbers is 40. :)
Answer:
<u>Applying Heron's Formula</u>
Now,
<u>Total Area: </u>
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<u>OAmalOHopeO</u>
Notice that 56° = 45° + 11°. Then
tan(56°) = sin(56°) / cos(56°)
… = sin(45° + 11°) / cos(45° + 11°)
… = (sin(45°) cos(11°) + cos(45°) sin(11°)) / (cos(45°) cos(11°) - sin(45°) sin(11°))
Recall that sin(45°) = cos(45°) = 1/√2, so we can cancel each term involving 45° :
tan(56°) = (cos(11°) + sin(11°)) / (cos(11°) - sin(11°))
The first step is to find out how question in total she is able to miss, while still passing.
We know that there are questions on the test and she must get % of the questions correct.
Let's calculate how many questions that is:
40 x 0.70
= 28.
<em>Subtract</em>
<em>40 - 28 </em>
<em>= 12.</em>
She is able to get 12 answers incorrect.
Now we must find out how many questions she got wrong when she got 40% of the first 15 correct.
If she got 40% correct; She got 60% incorrect.
Let's do the math:
<em>Multiply:</em>
<em>15 x 0.40</em>
<em>= 6</em>
<em>Subtract:</em>
<em>15 - 6 </em>
<em>= 9</em>
This means that she got 6 questions correct, and 9 questions incorrect.
With the total allotment of 12 incorrect answers allowed, she can only get 3 more questions wrong.
Now we must find the percentage of the remaining 25 questions she can get wrong.
She can only get 3 wrong and she must get 22 correct.
<em />
<em>Multiply:</em>
<em>22 x 4 </em>
<em>= 88.</em>
This means that she has to get 88% of the remaining 25 questions correct.
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