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2 years ago

Suppose the population of a certain city is 5769 . It is expected to decrease to 4963 in 50 years. Find the percent decrease.

Mathematics

1 answer:

creativ13 [48]2 years ago

4 0

Answer:

≈ 13.98%

Step-by-step explanation:

As the total population is 5769 in the initial period, you must find the percentage that repesents 4963 that is the expected population.

4963/5769=0.8602

Then you multiply it by 100 to transform it into percentage

0.8602*100=86.02%

Then it's just necesary to subtract that from 100% and that numbers is the percentage of decrease

100% - 86.02% = 13.98%

Also you can say that is approximately 14%

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2 years ago

X + 2y =6 X- y =3 Solution?

VikaD [51]

Since one equation has a negative y and the other has a positive y, I'm going to use those since they cancel each other out. Before that, the two y's need to be equal to each other.

x+2y=6
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Multiply the bottom equation by two so then you have:

x+2y=6
2x-2y=6

The y's now cancel out:

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Divide

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Subtract four

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Divide each

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y=1

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The answer is:
x=4
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I hope that helps!

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2 years ago

Read 2 more answers

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Semenov [28]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

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2 years ago