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3 years ago

Please I’ve been stuck on this question

Mathematics

2 answers:

shutvik [7]3 years ago

6 0

Answer: b

Step-by-step explanation:

Zielflug [23.3K]3 years ago

3 0

The answer is C. 6.

you would divide 9 by 6 to get 1.5. then multiply 4 by 1.5 to get 6.

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3 years ago

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sammy [17]

Answer:

DQ = $\frac{5}{(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}-\sqrt{x+h})}$

Step-by-step explanation:

Given function is f(x) = $\frac{5}{2-\sqrt{x}}$

f(x + h) = $\frac{5}{2-\sqrt{x+h} }$

Therefore, indicated difference quotient will be,

DQ = $\frac{f(x+h)-f(x)}{h}$

Now we substitute the values in the difference quotient,

DQ = $\frac{\frac{5}{2-\sqrt{x+h} }-\frac{5}{2-\sqrt{x}}}{h}$

= $\frac{5(2-\sqrt{x})-5(2-\sqrt{x+h})}{h(2-\sqrt{x})(2-\sqrt{x+h})}$

= $\frac{10-5\sqrt{x}-10+5\sqrt{x+h}}{h(2-\sqrt{x})(2-\sqrt{x+h})}$

= $\frac{-5\sqrt{x}+5\sqrt{x+h}}{h(2-\sqrt{x})(2-\sqrt{x+h})}$

= $\frac{5(-\sqrt{x}+\sqrt{x+h})}{h(2-\sqrt{x})(2-\sqrt{x+h})}$

= $\frac{5(-\sqrt{x}+\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}{h(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}$

= $\frac{5[(x+h)-x]}{h(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}$

= $\frac{5h}{h(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}$

= $\frac{5}{(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}$

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3 years ago