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almond37 [142]
4 years ago
8

The applicants for a soccer coaching position were asked how many years of

Mathematics
1 answer:
Naily [24]4 years ago
8 0

On this problem you have to make sure the dot plot and the dots on it match the ones for the problem. It should only have one dot for 1, 4 for 2's, 2 for 4's...etc.

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A nationwide survey of 100 boys and 50 girls in the first grade found that the daily average number of boys who are absent from
dusya [7]
Te difference of 2 standard deviation of a population n1 & n2 is given by the formula:
sigma (difference)=√(sigma1/n1 + sigma2/n2), Plug:

sigma(d)= √(49/100 + 36/50)

Sigma(d=difference) =1.1

6 0
4 years ago
Read 2 more answers
The circumference is 1 mile. What is the diameter?
iren2701 [21]

Answer:

Step-by-step explanation:

circumference  = 2* pi * radius = 1

-> radius = 0.1592 mile

-

> diameter = 2* radius = 0.31847 mile

8 0
3 years ago
The coordinates of points A and L are negative 4 and 8, respectively. What is the coordinate of the midpoint between them?
olga nikolaevna [1]
The midpoints between 4 and 8 would be 6 because 4 5 6 7 8, the middle term is 6
6 0
3 years ago
Consider the logarithms base 5. For each logarithmic expression below, either calculate the value of the expression or explain w
Tom [10]

Answer:

log₅(3125) = 5

Step-by-step explanation:

Given:

log₅(3125)

Now,

using the property of log function that

logₐ(b) = \frac{\log(b)}{\log(a)}

thus,

Therefore, applying the above property, we get

⇒ \frac{\log(3125)}{\log(5)}   (here log = log base 10)

now,

3125 = 5⁵

thus,

⇒  \frac{\log(5^5)}{\log(5)}

Now,

we know from the properties of log function that

log(aᵇ) = b × log(a)

therefore applying the above property we get

⇒ \frac{5\log(5)}{\log(5)}

or

⇒ 5

Hence,

log₅(3125) = 5

8 0
3 years ago
50+51+52+...+101=...<br>Can you help me? I do not understand
Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

But S=S^*, as we pointed out, so

2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926

5 0
3 years ago
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