Answer:
Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:
Plug -2 for one of the slopes.
Divide by -2 to find the slope of our line.
Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:
Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:
Simplify and distribute:
Subtract 4 from both sides:
The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
B: nine and one over two ft
This is an exponential decay problem.
Using the equation Y = a *(1-rate)^time
where Y is the future value given as 12,000 and a is the starting value given as 13,000.
The rate is also given as 5%.
The equation becomes:
12,000 = 13,000(1-0.05)^x
12,000 = 13,000(0.95)^x
Divide each side by 13000:
12000/13000 = 0.95^x/13000
12/13 = 0.95^x
Use the natural log function:
x = ln(12/13) / ln(0.95)
x = 1.56 years. ( this will equal 12,000
Round to 2 years it will be less than 12000.
For this case we have that by definition, the equation of the line of the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut point with the y axis.
By definition, if two straight lines are parallel then their slopes are equal. Thus, the slope of the line sought will be 
We substitute the given point to find b:
Finally the line is:
Answer:
Answer:
there is not accurate answer that can be give with that little amount of information
