<span> Draw a picture of the downward-facing </span>parabola<span>, and of a </span>rectangle<span> of the type described. Let (</span>x,y<span>) be the </span>upper<span> right-hand corner of the </span>rectangle<span>. Then by symmetry, the </span>base of the rectangle<span> has length </span>2x<span>, and the height is </span>y<span>, that is, </span>12−x2<span>. So the </span>area<span> A(</span>x<span>) of the </span>rectangle<span> is given by A(</span>x)=2x(12−x2<span>).</span>
<span>The cosine of pi/2 is 0 so the problem really says "find the angle between - pi/2 and pi/2 whose tan = 0. That would be the same as asking for the angle whose sin is 0. That would be 0.
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Answer:
6x²+10x
Step-by-step explanation:
2x(3x+5)
Distribute 2x to the terms in the bracket.
2x(3x) + 2x(5)
2x × 3x + 2x × 5
Multiply the terms.
6x²+10x
The answer is 6x²+10x.
Answer:
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Step-by-step explanation:
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