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Sliva [168]
3 years ago
13

What are the zeros of f(x) = x3 + 6x2 + 3x – 10 ?

Mathematics
1 answer:
schepotkina [342]3 years ago
3 0
One of the zeroes would be : x = 1

f (1)  = 1^3  + 6(1) ^2  + 3 (1)  - 10

f(1) = 1 + 6 + 3 - 10

f (1)  = 10 - 10

f (1) = 0

Hope this helps
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What is the equation, in standard form, of a parabola that models the values in the table? x~ -1 0 2
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<h2>Steps</h2>
  • Standard Form Equation: f(x) = ax² + bx + c

So firstly, since (0,5) is one of our values we can plug it into the standard form equation to solve for the c variable (since 0 will cancel out the a and b variable):

5=a*0^2+b*0+c\\5=c

Now we know that the value of c is 5. Next, plug in (-1,12) into the standard form equation and simplify (remember to also plug in 5 for the c variable):

12=a*(-1)^2+b*(-1)+5\\12=a-b+5\\7=a-b

Next, plug (2,15) into the standard form equation and simplify:

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Now, with our last two simplified equations we will create a system of equations:

7=a-b\\5=2a+b

Now, I will be using the elimination method with this system. With the system, add up the equations together and you will get:

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4=a

Now that we know the value of a, plug it into either equation to solve for the b variable:

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<h2>Answer</h2>

Putting all of our obtained values together, your final answer is:

f(x)=4x^2-3x+5

8 0
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Answer:

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Step-by-step explanation:

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3. Now, you must choose the common prime numbers with the lowest exponents and multiply them:

(2^{2})(3^{2})=(4)(9)=36


4 0
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Answer:

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