What are the zeros of f(x) = x3 + 6x2 + 3x – 10 ?

1 answer:

3 0

One of the zeroes would be : x = 1

f (1) = 1^3 + 6(1) ^2 + 3 (1) - 10

f(1) = 1 + 6 + 3 - 10

f (1) = 10 - 10

f (1) = 0

Hope this helps

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