Multiplying out the equation (x + 2)(4x - 3) and arranging in descending powers order gives us the quadratic form as; 4x² + 5x - 6
<h3>How to expand quadratic equations?</h3>
We want to expand the quadratic equation given as;
(x + 2)(4x - 3)
Multiplying out gives us;
4x² + 8x - 3x - 6
⇒ 4x² + 5x - 6
Thus, we can conclude that multiplying out the equation (x + 2)(4x - 3) and arranging in descending powers order gives us the quadratic form as; 4x² + 5x - 6
Read more about Quadratic equations at; brainly.com/question/1214333
#SPJ1
Answer:
x > - 5
x < 10
Step-by-step explanation:
Divide 7x>-35 by 7
Divide - 5x>-50 by - 5
Since we divide by a negative whe change the inequality sign.
Are you sure you've copied down the original problem exactly as given? i38 = 38i can't be simplified. Perhaps you meant i^38, which is a different matter.
Note that i^38 = i^32 * I^4 * I^2.
Note that i^0, i^4, i^8, etc., all equal 1. Therefore,
i^38 = (1)(1)i^2 = 1*(-1) = -1 (answer)
<h2>
Answer: 20°</h2>
<h3>
Step-by-step explanation:</h3>
Supplementary angles sum up to 180 °
Complementary angles sum up to 90°.
The supplement of 110° = 180° - 110° = 70°
The complement of 70° = 90° - 70° = 20°
<u>Simplier version:</u>
The complement of the supplement of 110° = (90° - (180° - 110°))
= 20°
