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4vir4ik [10]
3 years ago
5

How can you add, subtract, and multiply with decimal

Mathematics
1 answer:
kifflom [539]3 years ago
5 0
To add or subtract you do what you would normally do then put
the decimal in the answer

to multiply you multiply the numbers then add the demical places from both 
numbers then put the decimal there
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The population of a small town increased by 25% two years ago and then decreased by by 25% last year. The population is now 4500
nlexa [21]
9,000. It decreased by 50% (25%+25%) over three years, which in this case won't matter, because of the question. If 4,500 is 50% of <em /><em>x</em> then just multiply 4,500 by two.
6 0
4 years ago
Jonah received $300 in cash gifts for his fourteenth birthday. the function y remaining after x week if Jonah spends $25 each we
Alex Ar [27]
Assume that y its Jonah's cash and its initially 3000
y=300
But he spends 25/week. Assume that x is number of weeks.
y=300-25*x - its our function
If we want to find Jonahs cash after 9 week we have to substitute x=9, so
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4 0
3 years ago
What is 1/8 out of sixteen
Oksana_A [137]
1/8 * 16
= 16/8
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1/8 of 16 is 2 :)
7 0
4 years ago
Read 2 more answers
What is the simplified expression for 2(x - 5)?
charle [14.2K]
If you would like to know the simplified expression for 2 * (x - 5), you can find this using the following steps:

2 * (x - 5) = 2 * x - 2 * 5 = 2 * x - 10

The correct result would be <span>2 * x - 10.</span>
8 0
4 years ago
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If f(x)=2x-6 and g(x)=x^3 what is (g f)(0)
kow [346]
<h2>Hello!</h2>

The answer is:

(g\circ f)(0)=-216

<h2>Why?</h2>

To composite functions, we need to evaluate functions in another function(s), for example:

Given f(x) and g(x), if we want to calculate f(x) composite g(x), we need to evaluate g(x) into f(x).

So, we are given the functions:

f(x)=2x-6\\g(x)=x^{3}

And we are asked to calculate g(x) composite f(x), and then evaluate "x" to 0, so, calculating we have:

(g\circ f)(x)=g(f(x))\\\\(g\circ f)(x)=(2x-6)^{3}

Now that we have the composite function, we need to evaluate "x" equal to 0, so:

(g\circ f)(0)=(2x-6)^{3}\\\\(g\circ f)(0)=(2*(0)-6)^{3}=(0-6)^{3}=-6*-6*-6=-216

Hence, we have that:

(g\circ f)(0)=-216

Have a nice day!

6 0
4 years ago
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