Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
The answer is 5.9% I think because you have to round up if it’s 5 and above
Answer:
x≥−3
Step-by-step explanation:
−4x−10≤2
Step 1: Add 10 to both sides.
−4x−10+10≤2+10
−4x≤12
Step 2: Divide both sides by -4.
−4x−4≤12
−4
x≥−3
Find the volume of 1 car by multiplying the length by the width by the height:
Volume of 1 car = 20 x 10 x 10 = 2000 cubic feet.
Now multiply the volume of 1 car by the total number of cars:
2000 x 100 = 200,000 cubic feet total.
3(5x+2)=8x+20
15x+6=8x+20
15x-8x=20-6
7x=14
then you divide both sides by 2
The answer is 2.
